Answer:
where L is the length of the ramp
Explanation:
Let L (m) be the length of the ramp, and g = 9.81 m/s2 be the gravitational acceleration acting downward. This g vector can be split into 2 components: parallel and perpendicular to the ramp.
The parallel component would have a magnitude of
We can use the following equation of motion to find out the final velocity of the book after sliding L m:
where v m/s is the final velocity, 
= 0m/s is the initial velocity when it starts from rest, a = 2.87 m/s2 is the acceleration, and 
is the distance traveled:
Answer:
Ro=m/V
2.7 (g/cm^3)=2700(g) /V
V=2700 g/ 2.7 (g/cm^3)
V=2700/2.7=1000 cm^3
Explanation:
you volume is 1000 cubic centimeter
density dimension is g/cm^3
Answer:
water heat evaporated small tiny molecules form coluds .then clouds fall it rains at mountains.the water moves down to rivers,lakes.then again water evaporated rain falls . evaporated vapour it cools form water
Answer:
a) t1 = v0/a0
b) t2 = v0/a0
c) v0^2/a0
Explanation:
A)
How much time does it take for the car to come to a full stop? Express your answer in terms of v0 and a0
Vf = 0
Vf = v0 - a0*t
0 = v0 - a0*t
a0*t = v0
t1 = v0/a0
B)
How much time does it take for the car to accelerate from the full stop to its original cruising speed? Express your answer in terms of v0 and a0.
at this point
U = 0
v0 = u + a0*t
v0 = 0 + a0*t
v0 = a0*t
t2 = v0/a0
C)
The train does not stop at the stoplight. How far behind the train is the car when the car reaches its original speed v0 again? Express the separation distance in terms of v0 and a0 . Your answer should be positive.
t1 = t2 = t
Distance covered by the train = v0 (2t) = 2v0t
and we know t = v0/a0
so distanced covered = 2v0 (v0/a0) = (2v0^2)/a0
now distance covered by car before coming to full stop
Vf2 = v0^2- 2a0s1
2a0s1 = v0^2
s1 = v0^2 / 2a0
After the full stop;
V0^2 = 2a0s2
s2 = v0^2/2a0
Snet = 2v0^2 /2a0 = v0^2/a0
Now the separation between train and car
= (2v0^2)/a0 - v0^2/a0
= v0^2/a0
The student can measure a liquid's volume by using a graduated cylinder, or a beaker. Mass can be measured by first weighing an empty container on a scale, and then by adding the liquid to the container and weighing it again.
