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marissa [1.9K]
4 years ago
10

NEED HELP!! WILL GIVE BRAINIEST!! When a driver presses the brake pedal, his car can stop with an acceleration of -5.4 meters pe

r second squared. how far will the car travel while coming to a complete stop if its initial speed was 25 meters per second?
Physics
2 answers:
nexus9112 [7]4 years ago
7 0

Answer:

d = 57.87 m

Explanation:

It is given that,

Acceleration of car due to applied brake is -5.4\ m/s^2

Its initial speed was 25 m/s

Its final speed was 0 as its comes to rest.

Leat d is the distance covered by the car. It can be calculated using third equation of kinematics as :

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-(25)^2}{2\times (-5.4)}\\\\d=57.87\ m

So, the distance covered by the car is 57.87 m.

8_murik_8 [283]4 years ago
3 0

Answer:

d = 57.87 m

Explanation:  have a nice day :)

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When a 4.20-kg object is hung vertically on a certain light spring that obeys Hooke's law, the spring stretches 2.00 cm. (a) If
mr_godi [17]

(a) 0.714 cm

First of all, we need to find the spring constant of the spring. This can be done by using Hooke's law:

F=kx

where

F is the force applied on the spring

k is the spring constant

x is the stretching of the spring

At the beginning, the force applied is the weight of the block of m = 4.20 kg hanging on the spring, therefore:

F=mg=(4.20)(9.8)=41.2 N

The stretching of the spring due to this force is

x = 2.00 cm = 0.02 m

Therefore, the spring constant is

k=\frac{F}{x}=\frac{41.2}{0.02}=2060 N/m

Now, a new object of 1.50 kg is hanging on the spring instead of the previous one. So, the weight of this object is

F=mg=(1.50)(9.8)=14.7 N

And so, the stretching of th spring in this case is

x=\frac{F}{k}=\frac{14.7}{2060}=0.00714 m = 0.714 cm

(b) 1.65 J

The work done on a spring is given by:

W=\frac{1}{2}kx^2

where

k is the spring constant

x is the stretching of the spring

In this situation,

k = 2060 N/m

x = 4.00 cm = 0.04 m is the stretching due to the external agent

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8 0
4 years ago
What is an electric fuse? What is the working principle of electric fuse?
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3 years ago
If you have two linear polarizers whose extinction axis are 90 degrees relative to eachother, no light passes through the system
marin [14]

Answer:

The third polarizer can be placed midway between the first two polarizers with its extinction axis at 45° from either polarizer to maximize the amount of light that is transmitted (one-eight).

Explanation:

If light is incident on a polarizer, it allows only light that is parallel to its 'pass-through' axis to pass through untouched.

Light whose electric direction/vector is perpendicular to the 'pass through' axis will not pass through at all. Light whose electric direction/vector points in other directions (apart from those whose direction is parallel or perpendicular) passes through according to the magnitude of the component that is parallel to the 'pass-through' axis.

The polarizer blocks half of the incident light rays and the transmitted light is polarized in the direction of the 'pass-through' axis.

A new polarizer now place at a distance from the first polarizer with its 'pass-through' axis perpendicular to the first polarizer cancel out all the light that comes through from the first polarizer. Since the light electric vector needs to be parallel to the axis of the polarizer to pass through and all the parallelized light from the first polarizer are now incident perpendicularly to the axis of the second polarizer, no light rays pass through.

But, a third polarizer can be placed midway between the first two polarizers with its axis positioned at 45° from either polarizer. Thereby allowing exactly half of the light from the first polarizer to pass through. The explanation is just like that for the first one. (Light whose electric direction/vector points in other directions (apart from those whose direction is parallel or perpendicular) passes through according to the magnitude of the component that is parallel to the 'pass-through' axis).

Then the resultant from the middle polarizer reaches the initial second polarizer and half of the light is let through again. So that, at the end of the day, (1/2) × (1/2) × (1/2) of the initial incident ray is let through.

That is, to maximize the amount of light that is transmitted (one-eight of initial incident ray) the third Polaroid is place midway between the first two and at angle 45° to either one.

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