Calculate the time it takes for the car to reach the beginning of the hill given that acceleration as already found in part a is 2.89 m/s²
Answer:
5.88 s
Explanation:
Using kinematic equation, v=u+at where v and u are the final and initial velocities respectively, a is acceleration and t is time.
Considering the first part, acceleration is already found as 2.89 m/s and the final velocity is given as 17 m/s while the initial velocity is zero since it is at rest.
Making t the subject of formula then
t=(v-u)/a
Substituting the given figures then
t=(17-0)/2.89=5.8823529411764s
Rounded off, t=5.88 s
Opposite charges attract; like charges repel :)
it is violet , because it has the highest energy and fastest oscillation .
Answer:
Time to pass the train=0.05 h
How far the car traveled in this time=4.75 Km
Explanation:
We have that the train and the car are moving in the same direction, the difference between the speed of the vehicles is:

We will use this difference in the speed of the car an train to calculate how much time take the car to pass the train. For this we have that the train is 1km long and the car is moving with a speed of 20km/h (we use this value because is the speed that the car have in advantage of the train) then for a movement with a constant speed we have:

Where x is the distance, t is the time and v is the speed. using the data that we have:

This is the time that the car take to pass the train. Now to calculate how far the car have traveled in this time we have to considered the speed of 95Km/h of the car, then:

Answer:
Angular momentum, 
Explanation:
It is given that,
Radius of the axle, 
Tension acting on the top, T = 3.15 N
Time taken by the string to unwind, t = 0.32 s
We know that the rate of change of angular momentum is equal to the torque acting on the torque. The relation is given by :

Torque acting on the top is given by :

Here, F is the tension acting on it. Torque acting on the top is given by :





So, the angular momentum acquired by the top is
. Hence, this is the required solution.