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leonid [27]
3 years ago
6

in a fission or fusion reaction, what is true about the mass of the reactants compared to the mass of the products

Physics
1 answer:
Sati [7]3 years ago
4 0
Answer: <span>the mass of the reactants is greater than the mass of the products.</span>
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The pressure difference, , across a partial blockage in an artery (called a stenosis) is approximated by the equation where is t
Strike441 [17]

The question is incomplete. The complete question is  :

The pressure difference, Δp, acK_uross a partial blockage in an artery (called a stenosis) is approximated by the equation :

$\Delta p=K_v\frac{\mu V}{D}+K_u\left(\frac{A_0}{A_1}-1\right)^2 \rho V^2$

Where V is the blood velocity, μ the blood viscosity {FT/L2}, ρ the blood density {M/L3}, D the  artery diameter, A_0 the area of the unobstructed artery, and A1 the area of the stenosis.  Determine the dimensions of the constants K_v and K_u. Would this equation be valid in any  system of units?

Solution :

From the dimension homogeneity, we require :

$\Delta p=K_v\frac{\mu V}{D}+K_u\left(\frac{A_0}{A_1}-1\right)^2 \rho V^2$

Here, x means dimension of x. i.e.

$[ML^{-1}T^{-2}]=\frac{[K_v][ML^{-1}T^{-1}][LT^{-1}]}{[L]}+[K_u][1][ML^{-3}][L^2T^{-2}]$

                    $=[K_v][ML^{-1}T^{-2}]+[K_u][ML^{-1}T^{-2}]$

So, $[K_u]=[K_v]=[1 ]=$ dimensionless

So, K_u and K_v  are dimensionless constants.

This equation will be working in any system of units. The constants K_u and K_v will be different for different system of units.

5 0
3 years ago
Which of these statements about family relationships is true on Colonel Lloyd’s plantation?
Sergio [31]
Hello!

I'm unfamiliar with the book you are reading,

However, based on textual evidence, I think your answer relies somewhere in answer choice A or D.

I hope this helps!
6 0
3 years ago
Read 2 more answers
I need an answer asap
gulaghasi [49]
He has a mass of 56 kg.

The equation given is PE = mgh.

PE = 4620 J

h = 8.4

g = 9.8

Therefore:

4620 = 82.32m

m = 4620/82.32
m = 56 (rounded to two significant digits)
5 0
3 years ago
A 285-mL flask contains pure helium at a pressure of 750 torr . A second flask with a volume of 455 mL contains pure argon at a
zaharov [31]

Answer:

P_{He}^|=288.85torr

Explanation:

Given data

P_{He}=750 torr\\V_{He}=285mL\\P_{Ar}=732 torr\\V_{Ar}=455 mL

Required

Partial pressure of helium

Solution

First calculate the total volume of gas mixture once the stopcock is opened

So

V_{total}=V_{He}+V_{Ar}\\V_{total}=285mL+455mL\\V_{total}=740mL

As temperature remains constant,by Boyle's Law we calculate the partial pressure of the helium gas

So

P_{He}V_{He}=P_{He}^|V_{total}\\P_{He}^|=\frac{P_{He}V_{He}}{V_{total}}\\P_{He}^|=\frac{750torr*285mL}{740mL}\\  P_{He}^|=288.85torr

5 0
3 years ago
Read 2 more answers
Please help me , I also have to show work on paper
kramer

Answer:

Choose B

Explanation:

Hope Can I help you

7 0
3 years ago
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