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lara [203]
3 years ago
8

What is the volume of 15.2 grams of SO2 at STP?

Chemistry
1 answer:
kiruha [24]3 years ago
5 0

5.512 litres is the volume of  15.2 grams of sulphur dioxide gas at STP.

Explanation:

Data given:

mass of sulphur dioxide = 15.2 grams

conditions is at STP whech means volume = 22.4 litres

atomic mass of sulphur dioxide = 64.06 grams/mole

Number of moles is calculated as:

number of moles = \frac{mas}{atomic mass of 1 mole}

Putting the values in the equation:

number of moles = \frac{15.2}{64.06}

                              = 0.23 moles

Assuming that sulphur dioxide behaves as an ideal gas, we can calculate the volume as:

When 1 mole of sulphur dioxide occupies 22.4 litres at STP

Then 0.23 moles of sulphur dioxide occupies 22.4 x 0.23

= 5.152 litres is the volume.

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Answer:

The answer to your question is:

Explanation:

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5.- VII A Halogen

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8.-                              Categories of the periodic table

Metals                                 Metalloids                            Non-metals

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3 0
2 years ago
Fassst. A or b or c or d plzzz
AVprozaik [17]
C, an elliptical motion
7 0
3 years ago
Read 2 more answers
During a spectrophotometric analysis of an unknown, you measure your solution's absorbance, and the value is higher than the hig
Reil [10]

Answer:

A) Dilute the unknown so that it will have an absorbance within the standard curve. Once the diluted unknown concentration is determined, the full strength concentration can be calculated if the dilution process is recorded. Beer's law only applies to dilute solutions, so diluting the unknown is better than making new standards.

Explanation:

Beer's law states that <em>absorbance is proportional to the concentrations of the absorbing species</em>. This is verified in the case of diluted solutions (0≤0.01 M) of most substances. <u>As a solution gets more concentrated, solute molecules interact between themselves because of their proximity. </u>When a molecule interacts with another, the change in their electric properties (including absorbance) is probable. That's why <u>the plot of absorbance versus concentration stops being a straight line</u>, and <u>Beer's law is no longer valid.</u>

Therefore, if the absorbance value is higher than the highest standard,  dilutions should be made. Once this concentration is determined, the full strength concentration can be calculated with the inverse of the dilution.

7 0
3 years ago
Dolomite is a mixed carbonate of calcium and magnesium. Calcium and magnesium carbonates both decompose upon heating to produce
Setler79 [48]

Answer:

72.03 %

Explanation:

Total mass of dolomite = 9.66 g

Let the mass of Magnesium carbonate = x g

The mass of calcium carbonate = 9.66 - x g

Calculation of the moles of Magnesium carbonate as:-

Molar mass of Magnesium carbonate = 122.44 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{x\ g}{84.3139\ g/mol}=\frac{x}{84.3139}\ mol

Calculation of the moles of calcium carbonate as:-

Molar mass of calcium carbonate = 100.0869 g/mol

Thus,

Moles= \frac{9.66 - x\ g}{100.0869\ g/mol}=\frac{9.66 - x}{100.0869}\ mol

According to the reaction shown below:-

MgCO_3\rightarrow MgO+CO_2

CaCO_3\rightarrow CaO+CO_2

In both the cases, the oxides formed from the carbonates in the 1:1 ratio.

So, Moles of MgO = \frac{x}{84.3139}\ mol

Molar mass of MgO = 40.3044 g/mol

Thus, Mass = Moles*Molar mass = \frac{x}{84.3139}\times 40.3044 \ g

Moles of CaO = \frac{9.66 - x}{100.0869}\ mol

Molar mass of CaO = 56.0774 g/mol

Thus, Mass = Moles*Molar mass = \frac{9.66 - x}{100.0869}\times 56.0774 \ g

Given that total mass of the oxide = 4.84 g

Thus,

\frac{x}{84.3139}\times 40.3044 +\frac{9.66 - x}{100.0869}\times 56.0774=4.84

\frac{40.3044x}{84.3139}+56.0774\times \frac{-x+9.66}{100.0869}=4.84

-694.1618435x+45673.48749\dots =40843.38968\dots

x=\frac{4830.09780\dots }{694.1618435}

x=6.9582

Thus, the mass of Magnesium carbonate = 6.9582 g

\%\ mass=\frac{Mass_{MgCO_3}}{Total\ mass}\times 100

\%\ mass=\frac{6.9582}{9.66}\times 100=72.03\ \%

3 0
3 years ago
A gas occupies 40.0 mL at 150 K. What volume does it occupy at 300 K,
nlexa [21]

Answer:

.08 L or 80 ml

Explanation:

Use the equation V/t = V/t.

.04L / 150K = V / 300K

.04 / 150 * 300 = V

.08 L or 80 ml

6 0
3 years ago
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