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3 years ago

The sun sum of protons and neutrons in the nucleus of an atom.

1 answer:

7 0

Answer is the mass of the atom. Protons + neutrons= mass
Let's say you have oxygen with a mass of 16.
Oxygen has 8 protons
To find neutrons subtract 16-8= 8
So it would also be 8 neutrons.
Example of how to find mass if you know protons + neutrons:
Sodium has 11 protons and 12 neutrons. Add the protons and neutrons
11 + 12= 23
Mass is 23

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Ksenya-84 [330]

Answer
B I’m pretty sure
Explanation

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2 years ago

Read 2 more answers

The specific heat capacity of a pure substance can be found by dividing the heat needed to change the temperature of a sample of

kupik [55]

Answer:

See below

Explanation:

ΔQ = m c T ΔQ = heat required(J) m = mass (g) T = C° temp change

c = heat capacity in J/g-C

4 0

2 years ago

The solubility of silver(I)phosphate at a given temperature is 1.02 g/L. Calculate the Ksp at this temperature. After you get yo

Snezhnost [94]

Answer: The solubility product of silver (I) phosphate is $9.57\times 10^{-10}$

Explanation:

We are given:

Solubility of silver (I) phosphate = 1.02 g/L

To convert it into molar solubility, we divide the given solubility by the molar mass of silver (I) phosphate:

Molar mass of silver (I) phosphate = 418.6 g/mol

$\text{Molar solubility of silver (I) phosphate}=\frac{1.02g/L}{418.6g/mol}=2.44\times 10^{-3}mol/L$

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The chemical equation for the ionization of silver (I) phosphate follows:

$Ag_3PO_4(aq.)\rightleftharpoons 3Ag^{+}(aq.)+PO_4^{3-}(aq.)$

3s s

The expression of $K_{sp}$ for above equation follows:

$K_{sp}=(3s)^3\times s$

We are given:

$s=2.44\times 10^{-3}M$

Putting values in above expression, we get:

$K_{sp}=(3\times 2.44\times 10^{-3})^3\times (2.44\times 10^{-3})\\\\K_{sp}=9.57\times 10^{-10}$

Hence, the solubility product of silver (I) phosphate is $9.57\times 10^{-10}$

4 0

2 years ago

Q2. Which of these is a mixture?

iVinArrow [24]

The answer is sodium chloride

7 0

2 years ago

What is the new pressure of 150 mL of a gas that is compressed to 50 mL when the original pressure was 3.0 ATM and the temperatu

Arisa [49]

Answer:

$\boxed {\boxed {\sf P_2= 9 \ atm}}$

Explanation:

Since the temperature is held constant, we only need to focus on the volume and pressure. We will use Boyle's Law, which states the volume of a gas is inversely proportional to the pressure. The formula is:

$P_1V_1=P_2V_2$

Originally, the gas had a volume of 150 milliliters and a pressure of 3.0 atmospheres. We can substitute these values into the left side of the equation.

$3.0 \ atm * 150 \ mL = P_2V_2$

The original gas was compressed to a volume of 50 milliliters, but we don't know the volume.

$3.0 \ atm *150 \ mL= P_2 * 50 \ mL$

Now, we need to solve for the new pressure (P₂). Multiply on the left side first.

$450 \ atm*mL= P_2 * 50 \ mL$

Since we are solving for the pressure, we need to isolate the variable. It is being multiplied by 50 mL. The inverse of multiplication is division. Divide both sides by 50 mL.

$\frac{450 \ atm*mL}{50 \ mL}= \frac{P_2 * 50 \ mL}{50 \ mL}$

$\frac{450 \ atm*mL}{50 \ mL}= P_2$

The units of milliliters will cancel.

$\frac{450 \ atm}{50 }= P_2$

$9 \ atm =P_2$

The new pressure is 9 atmospheres.

8 0

2 years ago