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2 years ago

The sun sum of protons and neutrons in the nucleus of an atom.

1 answer:

7 0

Answer is the mass of the atom. Protons + neutrons= mass
Let's say you have oxygen with a mass of 16.
Oxygen has 8 protons
To find neutrons subtract 16-8= 8
So it would also be 8 neutrons.
Example of how to find mass if you know protons + neutrons:
Sodium has 11 protons and 12 neutrons. Add the protons and neutrons
11 + 12= 23
Mass is 23

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n-Butane fuel (C4H10) is burned with the stoichiometric amount of air. Determine the mass fraction of each product. Also, calcul

tia_tia [17]

Answer:

0.1852
0.0947
0.7201
3.0345 kg CO $_{2}$ / Kg C $_{4}$ H $_{10}$
15.3848 Kg air / kg C $_{4}$ H $_{10}$

Explanation:

Molar masses of each product are :

Butane = 58 kg /kmol

Oxygen = 32 kg/kmol

Nitrogen = 28 kg/kmol

water = 18 kg/kmol

1) Calculate the mass fraction of carbon dioxide

= ( 4 * 44 ) / ( (5 * 18) + (4 *44 )+ (24.44 * 28) )

= 176 / 950.32

= 0.1852

2) Calculate the mass fraction of water

= ( 5 * 18 ) / (( 5* 18 ) + ( 4*44) + ( 24.44 * 28 ))

= 90 / 950.32

= 0.0947

3) Calculate the mass fraction of Nitrogen

= (24.44 * 28 ) / ((4 * 44 ) + ( 24.44 * 28 ) + ( 5 * 18 ))

= 684.32 / 950.32

= 0.7201

4) Calculate the mass of Carbon dioxide in the products

Mco2 = ( 4 * 44 ) / 58 = 3.0345 kg CO $_{2}$ / Kg C $_{4}$ H $_{10}$

5) Mass of Air required per unit of fuel mass burned

Mair = ( 6.5 * 32 + 24.44 *28 ) / 58 = 15.3848 Kg air / kg C $_{4}$ H $_{10}$

5 0

2 years ago

The salt NaC2H3O2 would form from the combination of:

Nuetrik [128]

B sodium chloride and nitric acid

4 0

3 years ago

The weight of 112 liters of carbon dioxide at STP would be 44.09. True or false?

marshall27 [118]

Answer:

False

Explanation:

Its false

3 0

2 years ago

Determine the change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizi

uysha [10]

Answer: The change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizing compound is dissolved in it is $2.9^0C$

Explanation:

Elevation in boiling point:

$T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of pure carbon disulfide= $46.2^oC$

$k_b$ = boiling point constant = $2.34^0Ckg/mol$

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

$w_2$ = mass of solute = 35.0 g

$w_1$ = mass of solvent (carbon disulphide) = 397.7 g

$M_2$ = molar mass of solute = 70.0 g/mol

Now put all the given values in the above formula, we get:

$(T_b-46.2)^oC=1\times (2.34^oC/m)\times \frac{(35.0g)\times 1000}{70.0\times (397.7g)}$

$T_b=49.1^0C$

Therefore, the change in boiling point is $(49.1-46.2)^oC=2.9^0C$

5 0

3 years ago

A chemist prepares a solution of copper(II) fluoride by measuring out of copper(II) fluoride into a volumetric flask and filling

Simora [160]

The question is incomplete, here is the complete question.

A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.

Answer: The concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

Explanation:

To calculate the molarity of solute, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of copper (II) fluoride = 0.0498 g

Molar mass of copper (II) fluoride = 101.54 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

$\text{Molarity of copper (II) fluoride)=\frac{0.0498\times 1000}{101.54\times 100.0}\\\\\text{Molarity of copper (II) fluoride}=4.90\times 10^{-3}mol/L$

Hence, the concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

4 0

2 years ago