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Cerrena [4.2K]
4 years ago
7

Calculate the molarity (m) of a solution prepared by dissolving 10.7 g nai in 0.250 l.

Chemistry
2 answers:
Lilit [14]4 years ago
7 0
Molarity is defined as the number of moles of solute in 1 L of solution 
number of moles of NaI - 10.7 g / 150 g/mol = 0.0713 mol 
there are 0.0713 mol in 0.250 L
we need to find the number of NaI moles in 1 L
if 0.250 L contains - 0.0713 mol 
then 1 L contains - 0.0713 mol / 0.250 L  = 0.285 mol/L
molarity is 0.285 M
melisa1 [442]4 years ago
6 0

Answer:

0,285M

Explanation:

The molarity of a solution is defined as moles of solute per liter of solution.

If you are dissolving NaI in 0,250L, the NaI is the solute and the volume of the solution is 0,250L.

Knowing molar mass of NaI is 150 g/mol, moles of NaI in 10,7g are:

10,7g × (1mol / 150g) = <u><em>0,0713 moles of NaI</em></u>

As the volume of solution is 0,250L, molarity is:

M = 0,0713 moles of NaI / 0,250L = <em>0,285M</em>

<em></em>

I hope it helps!

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What is the diffence between solids , liquids and gases ?
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6 0
3 years ago
What volume of solution gives the desired moles?
motikmotik

Answer:

1. 0.073L

2. 0.028L

3. 0.014L

Explanation:

The volume for the different solutions are obtained as shown below:

1. Mole = 0.53mol

Molarity = 7.25M

Volume =?

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 0.53/7.25

Volume = 0.073L

2. 0.035mol from a 1.25M

Mole = 0. 035mol

Molarity = 1.25M

Volume =?

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 0.035/1.25

Volume = 0.028L

3. Mole = 0.0013mol

Molarity = 0.090M

Volume =?

Molarity = mole /Volume

Volume = mole /Molarity

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8 0
3 years ago
If the temperature of an ideal gas is raised from 100◦C to 200◦C, while the pressure remains constant, the volume 1. increases b
mel-nik [20]

Answer:

3. doubles

Explanation:

for an ideal gas behavior, the relationship between volume and temperature is given by Charles law

Charles law states that the volume of a given mass of gas is directly proportional to its temperature provided that pressure remains constant. Mathematically, this is represented as

V ∝ T

V=KT

K = V/T

where V is the volume of the gas

T is the Temperature

k represents the constant of proportionality

For initial and final conditions of a gas,

\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }

where 1 and 2 represent initial and final conditions respectively

therefore, T₁ = 100 and T₂ = 200

\frac{V_{1} }{100} = \frac{V_{2} }{200}

200 × V₁ = 100 × V₂

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3 0
3 years ago
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