Explanation:
Dehydrohalogenation reactions occurs as elimination reactions through the following mechanism:
Step 1: A strong base(usually KOH) removes a slightly acidic hydrogen proton from the alkyl halide.
Step 2: The electrons from the broken hydrogen‐carbon bond are attracted toward the slightly positive carbon (carbocation) atom attached to the chlorine atom. As these electrons approach the second carbon, the halogen atom breaks free.
However, elimination will be slower in the exit of Hydrogen atom at the C2 and C3 because of the steric hindrance by the methyl group.
Elimination of the hydrogen from the methyl group is easier.
Thus, the major product will A
According to Boyle's law, if the temperature were tripled as the number of moles and the volume were held constant, the pressure would triple (option C).
<h3>What is Boyle's law?</h3>
Boyle's law is the observation that the pressure of an ideal gas is inversely proportional to its volume at constant temperature.
However, when the temperature of a gas is increased, the pressure of the gas also increases provided the volume is constant.
According to this question, the temperature of a gas tripled as the number of moles and the volume were held constant.
Therefore, according to Boyle's law, if the temperature were tripled as the number of moles and the volume were held constant, the pressure would triple.
Learn more about Boyle's law at: brainly.com/question/1437490
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The Answer Is B Because You Have To Divide The 9
Half reaction 1: 2Fe° → Fe₂³⁺ + 6e⁻ /×2.
4Fe° → 2Fe₂³⁺ + 12e⁻.
Iron is oxidized from neutral charge (0) to oxidation number +3, one iron lose three electrons, two irons lose six electrons and four irons twelve electrons.
Half reaction 2: 12e⁻ + 3O₂ → 2O₃²⁻
Oxygen is reduced from neutral chage to oxidation number -2, one oxygen gain two electrons, six oxygens gain twelve electrons.
Balanced chemical reaction: 4Fe + 3O₂ → 2Fe₂O₃.
