The length of a copper wire is 1.6 centimeters (cm). What is the length of this wire in meters (m)?

Baker’s yeast catalyzes the decomposition of hydrogen peroxide (dihydrogen dioxide) into oxygen and water. Directions: Add 10 mL

andreev551 [17]

Answer:

The unbalanced chemical equation: H₂O₂ → H₂O + O₂.

The balanced chemical equation: H₂O₂ → H₂O + 1/2O₂.

Explanation:

Hydrogen peroxide is decomposed into oxygen and water, which is a slow reaction.

It is can be catalyzed by using yeast.

The unbalanced chemical equation: H₂O₂ → H₂O + O₂.

The balanced chemical equation: H₂O₂ → H₂O + 1/2O₂.

1.0 mol of H₂O₂ is decomposed to 1.0 mol of H₂O and 0.5 mol of O₂.

3 0

3 years ago

A compound's properties are different than the properties of the elements that make it up.

yan [13]

The answer is True because elements in a compound combine and become an entirely different substance with its own unique properties.

7 0

3 years ago

Select the properly written and balanced equation for the following chemical reaction: Sodium metal and an aqueous solution of m

Setler [38]

Answer: $2Na(s)+MgI_2 (aq)\rightarrow 2NaI(aq)+Mg(s)$

Explanation: The chemical reaction is written by writing down the chemical formulas of the reactants on the left hand side and the chemical formulas of products on the right hand side separated by a right arrow.

This is a single displacement reaction in which a more reactive element displaces the less reactive element from its salt solution. Thus sodium is more reactive than Mg and thus displaces it from $MgI_2$ .

$2Na(s)+MgI_2 (aq)\rightarrow 2NaI(aq)+Mg(s)$

The number of atoms of each element must be same on both sides of the reaction so as to follow the law of conservation of mass. Thus the equation is balanced.

5 0

3 years ago

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: E = R_y/n^2 In this equation R_y stands

Katarina [22]

Answer:

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is $5.23\times 10^{-5} m$

Explanation:

Given :

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:

$E=\frac{R_y}{n^2}$

$R_y=2.18\times 10^{-18} J$ = Rydberg energy

n = principal quantum number of the orbital

Energy of 11th orbit = $E_{11}$

$E_{11}=\frac{2.18\times 10^{-18} J}{11^2}=1.80\times 10^{-20} J$

Energy of 10th orbit = $E_{10}$

$E_{10}=\frac{2.18\times 10^{-18} J}{10^2}=2.18\times 10^{-20} J$

Energy difference between both the levels will corresponds to the energy of the wavelength of the line which can be calculated by using Planck's equation.

$E'=E_{10}-E_{11}=2.18\times 10^{-20} J-1.80\times 10^{-20} J$

$=E'=0.38\times 10^{-20} J$

$\lambda =\frac{hc}{E'}$ (Planck's' equation)

$\lambda = \frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{0.38\times 10^{-20} J}$

$\lambda = 5.2310\times 10^{-5} m\approx 5.23\times 10^{-5} m$

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is $5.23\times 10^{-5} m$

3 0

3 years ago

A 1.0 M H2S solution has a pH = 3.75 at equilibrium. What is the value of Ka?

MrRa [10]

The answer is 3.16*10-8

7 0

3 years ago

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