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defon
2 years ago
11

a 22.44g sample of iron absorbs 180.8 J of heat, upon which the temperature of the sample increases from 21.1C to 39.0/ what is

the specific heat of iron
Chemistry
1 answer:
NeX [460]2 years ago
8 0

Answer:

The specific heat of iron is 0.45 J/g.°C

Explanation:

The amount of heat absorbed by the metal is given by:

heat = m x Sh x ΔT

From the data, we have:

heat = 180.8 J

mass = m = 22.44 g

ΔT = Final temperature - Initial temperature = 39.0°C - 21.1 °C = 17.9°C

Thus, we calculate the specific heat of iron (Sh) as follows:

Sh = heat/(m x ΔT)  = (180.8 J)/(22.44 g x 17.9°C) = 0.45 J/g.°C

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Explanation:

Let's first take account of what we have and convert them into the correct units.

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Molar mass is in grams per mole, or MM= \frac{mass}{moles} or MM= \frac{m}{n}. They're all the same.

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Let's look back at MM= \frac{m}{n} and plug in what we know.

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