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Len [333]
3 years ago
7

If energy increasing or decreasing as you go from a solid to a liquid

Chemistry
2 answers:
Gelneren [198K]3 years ago
8 0
The energy increases because the molecules in water move faster
yulyashka [42]3 years ago
6 0
I believe the energy decreases
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Because of movements at the Mid-Atlantic Ridge, the Atlantic Ocean widens by about 2.5 centimeters each year. Explain which type
slamgirl [31]

Answer:

A divergent plate boundary  

Explanation:

At a divergent boundary, the plates pull away from each other and generate new crust.

 

6 0
4 years ago
Read 2 more answers
A gas at constant volume has a pressure of 4. 50 atm at 200. K. What will be the pressure of the gas at 250. K? 3. 60 atm 4. 60
Trava [24]

5.625 atm will be the pressure of the gas at 250 K temperature of the gas at constant volume.

<h3>How we calculate the pressure of the gas?</h3>

Pressure of the gas will be calculated by using the ideal gas equation as:

PV = nRT,

From the question, it is clear that:

Moles of the gas and volume is constant here, so we calculate the pressure by rearranging the above equation as:

P/T = nR/V

And required equation will be:

P₁/T₁ = P₂/T₂, where

P₁ = pressure of gas = 4.50 atm

T₁ = temperature of gas = 200 K

P₂ = pressure of gas = to find?

T₂ = temperature of gas = 250 K

On putting all these values in the above equation, we get

P₂ = 4.50 × 250 / 200 = 5.625 atm

Hence, 5.625 atm is the pressure of the gas.

To know more about ideal gas equation, visit the below link:

brainly.com/question/1056445

5 0
3 years ago
in a particular breed of cattle a black coat is dominant over red coat if a cow with a red coat is crossed with a black bull tha
wolverine [178]
The percentage of offspring with a black coat would be roughly 50%
6 0
4 years ago
If 175 g of phosphoric acid reacts with 150.0 g of sodium hydroxide, what is the limiting reactant? How many grams of sodium pho
Evgen [1.6K]

Answer:

NaOH is the limiting reactant.

204.9 g of sodium phosphate are formed.

51.94 g of excess reactant will remain.

Explanation:

The reaction that takes place is:

  • H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂O

First we <u>convert the mass of both reactants to moles</u>, using their <em>respective molar masses</em>:

  • H₃PO₄ ⇒ 175 g ÷ 98 g/mol = 1.78 mol
  • NaOH ⇒ 150 g ÷ 40 g/mol = 3.75 mol

1.78 moles of H₃PO₄ would react completely with (1.78 * 3) 5.34 moles of NaOH. There are not as many NaOH moles so NaOH is the limiting reactant.

--

We <u>calculate the produced moles of Na₃PO₄</u> using the <em>limiting reactant</em>:

  • 3.75 mol NaOH * \frac{1molNa_3PO_4}{3molNaOH} = 1.25 mol Na₃PO₄

Then we <u>convert moles into grams</u>:

  • 1.25 mol Na₃PO₄ * 163.94 g/mol = 204.9 g

--

We calculate how many H₃PO₄ moles would react with 3.75 NaOH moles:

  • 3.75 mol NaOH * \frac{1molH_3PO_4}{3molNaOH} = 1.25 mol H₃PO₄

We substract that amount from the original amount:

  • 1.78 - 1.25 = 0.53 mol H₃PO₄

Finally we <u>convert those remaining moles to grams</u>:

  • 0.53 mol H₃PO₄ * 98 g/mol = 51.94 g
3 0
3 years ago
A 2.0 mol ideal gas system is maintained at a constant volume of 4.0 L. If 100 J of heat is added, what is the work done on the
LuckyWell [14K]

Answer:

Work done on the system is zero , hence no work is done since the process is <u>isochoric.</u> There is no work done if the volume remains unchanged. (Though the temperature rises, work is only accomplished when the volume of the gas changes.)

Explanation:

ISOCHORIC PROCESS - An isochoric process, also known as a constant-volume process, isovolumetric process, or isometric process, is a thermodynamic process in which the volume of the closed system undergoing the process remains constant through the process. The heating or cooling of the contents of a sealed, inelastic container is an example of an isochoric process. The thermodynamic process is the addition or removal of heat, the closed system is established by the isolation of the contents of the container, and the constant-volume condition is imposed by the container's inability to deform. It should be a quasi-static isochoric process in this case.

<u>Hence , the work done in the system is zero.</u>

7 0
3 years ago
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