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denis-greek [22]
3 years ago
13

A Solution is a mixture of two or more substances_____

Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
4 0

Answer:

In the same phase

Explanation:

Because when you make a solution you have to keep them in the same phase or you will oof.

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THE CORRECT ANSWER IS COMMAND.HOPE IT HELP YOU

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2. When a teaspoonful of sugar is added to water in a beaker,
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Sugar + water = 2) a solution
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Gaseous methane (CH4) will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO) and gaseous water (H2O) . Suppo
Leto [7]

Answer:

0 g.

Explanation:

Hello,

In this case, since the reaction between methane and oxygen is:

CH_4+2O_2\rightarrow CO_2+2H_2O

If 0.963 g of methane react with 7.5 g of oxygen the first step is to identify the limiting reactant for which we compute the available moles of methane and the moles of methane consumed by the 7.5 g of oxygen:

n_{CH_4}=0.963gCH_4*\frac{1molCH_4}{16gCH_4}=0.0602molCH_4\\ \\n_{CH_4}^{consumed}=7.5gO_2*\frac{1molO_2}{32gO_2}*\frac{1molCH_4}{2molO_2} =0.117molCH_4

Thus, since oxygen theoretically consumes more methane than the available, we conclude the methane is the limiting reactant, for which it will be completely consumed, therefore, no remaining methane will be left over.

left\ over=0g

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7 0
3 years ago
What is the new pressure if the temperature outside is 296k and his weight causes the tire's volume to drop to 2.0 liters
sukhopar [10]

Question:

At standard temperature and pressure, the volume of a tire is 3.5L. What is the new pressure if the temperature outside is 296k and its weight causes the volume of the gas is 2.0 L?

Answer:

The new pressure is: 1.896 atm

Explanation:

At standard temperature and pressure, we have:

P_1 = 1atm

T_1 = 273.15k

V_1 = 3.5L

Outside, we have:

T_2 = 296k

V_2 = 2.0L

Required

Determine the new pressure

Using combined gas law, we have:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

This gives:

\frac{1 * 3.5}{273.15} =\frac{P_2*2.0}{296}

Solve for P_2

P_2 = \frac{296 * 1 * 3.5}{273.15*2.0}

P_2 = \frac{1036}{546.30}

P_2 \approx 1.896 atm

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How many types of kinetic energies are there? is it 4 or 5 types?
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