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stich3 [128]
3 years ago
12

2. In our bodies, carbon dioxode

Chemistry
1 answer:
ANEK [815]3 years ago
8 0
I’m not 100% sure but I’m thinking B or C
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Loops of gas that exit the sun is called what?
Bumek [7]
I hope this helps! please tell me if it’s wrong.

7 0
3 years ago
How many nonbonding electron pairs are there in the lewis structure of the peroxide ion, o22−?
Tom [10]
There is 6 non - bonding pairs.
Let me show you one easy method to do this.
o22-, oxygen valence electron = 6 here we have two so total 12, and -2 that means we add electrons so it’s all equal to 14 right.
whenever need to find lone pair, subtract the number you get with the lowest multiple of 8.
here we total 14 valence electron right so lowest multiple of 8 would be 8.
so 14 - 8 = 6 and that is our answer.
Let me know if you have Problem with chemistry.
8 0
3 years ago
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If the gram-formula mass of substance X is 180 g/mol, determine the molarity of the solution at Point E
Alina [70]
<h3><u>Answer;</u></h3>

<u>= 5 M or 5 moles/liter</u>

<h3><u>Explanation;</u></h3>

At point E, 90 g of substances X are dissolved in 100 g of the solvent.

100g of the solvent is equal to 100 ml

Molarity is the number of moles of a substance in one liter of a solvent.

90 g of X are in 100 ml

But; the RFM of X = 180 g/l

Therefore; the moles of X in 90 g = 90/180

                                                        = 0.5 moles

Therefore;

0.5 moles of X are contained in 100 ml of the solvent;

Thus, molarity = 0.5 × 1000/100

                       =<u> 5 M or 5 moles/liter</u>

7 0
3 years ago
A 0.753 g sample of a monoprotic acid is dissolved in water and titrated with 0.250 M NaOH. What is the molar mass of the acid i
Alexeev081 [22]

Answer:

MM_{acid}=140.1g/mol

Explanation:

Hello,

In this case, since the acid is monoprotic, we can notice a 1:1 molar ratio between, therefore, for the titration at the equivalence point, we have:

n_{acid}=n_{base} \\\\V_{acid}M_{acid}=V_{base}M_{base}\\\\n_{acid}=V_{base}M_{base}

Thus, solving for the moles of the acid, we obtain:

n_{acid}=0.0215L*0.250\frac{mol}{L}=5.375x10^{-3}mol

Then, by using the mass of the acid, we compute its molar mass:

MM_{acid}=\frac{0.753g}{5.375x10^{-5}mol} \\\\MM_{acid}=140.1g/mol

Regards.

7 0
2 years ago
Differences and similarities between Clastic, Chemical, and Organic sedimentary rock.
8090 [49]
Clastic are made from small pieces of other rocks, sedimentary rocks.
Chemical are formed when minerals becomes undersaturated, precipitate forming a limestone.
organic sedimentary rock are made of fossils
 
7 0
2 years ago
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