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riadik2000 [5.3K]
2 years ago
9

Write an equation for the line in the given form.

Mathematics
2 answers:
Dovator [93]2 years ago
6 0

Answer:

y=3x-13

Step-by-step explanation:

jek_recluse [69]2 years ago
4 0
Y is 3x,-12 THATS the answer
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Graph the following solution y=-1/2×+1 and y=-2/3×+2
Dovator [93]
I hope this helps!! Look at the top and the graph, don't know which answer you prefer :)

5 0
3 years ago
Three siblings are doing their washing and hanging all the items on the washing line.
Rom4ik [11]

Answer:

A.) Paul

B.) Plain

C.) Paul

Step-by-step explanation:

Paul: Shirt - Striped; Jumper - Spotted; Towel - Plain

Kerry: Shirt - Plain; Jumper - Striped; Towel - Spotted

Sandra: Shirt - Spotted; Jumper - Plain; Towel - Striped

Hope this helps! Have a nice dayy! :)

6 0
3 years ago
Need help with 12 and 13
EastWind [94]

Answer:

12: 7       13:  49

Step-by-step explanation:

35 divided by 5 is 7 so you would get the answer of 6 for 12

7x7 is 49

6 0
3 years ago
The area of a polygon is the number of square units contained in its interior true or false
Vsevolod [243]
<span>False. Perimeter is a linear measure. Square units are for area.</span>
5 0
3 years ago
Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar
klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack

Where (from tables):

Z_{0.99}=2.33

Finally, the interval at 98% confidence level is:

CI(\mu)=\lbrack28.94,31.06\rbrack

4 0
1 year ago
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