In that formula for Energy, 'F' is the frequency of the photon.
But <u>Frequency = (speed)/(wavelength)</u>, so we can write the
Energy formula as
E = h c / (wavelength) .
So the energy, in joules, of a photon with that wavelength, is . . .
E = (6.6 x 10⁻³⁴) x (3 x10⁸) / (that wavelength)
= <em>(1.989 x 10⁻²⁵) / (that wavelength, in meters) .</em>
Answer:
When you don't move, you still use energy. This energy is called potential energy, or, stored energy.
When you don't move or do work, you can use energy.
Answer:
P₁ = 2.215 10⁷ Pa, F₁ = 4.3 106 N,
Explanation:
This problem of fluid mechanics let's start with the continuity equation to find the speed of water output
Q = A v
v = Q / A
The area of a circle is
A = π r² = π d² / 4
Let's look at the speeds at each point
v₁ = Q / A₁ = Q 4 /π d₁²
v₁ = 10 4 /π 0.5²
v₁ = 50.93 m / s
v₂ = Q / A₂
v₂ = 10 4 /π 0.25²
v₂ = 203.72 m / s
Now we can use Bernoulli's equation in the colon
P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂
Since the tube is horizontal y₁ = y₂. The output pressure is P₂ = Patm = 1.013 10⁵ Pa, let's clear
P₁ = P2 + ½ rho (v₂² - v₁²)
P₁ = 1.013 10⁵ + ½ 1000 (203.72² - 50.93²)
P₁ = 1.013 10⁵ + 2.205 10⁷
P₁ = 2.215 10⁷ Pa
la definicion de presion es
P₁ = F₁/A₁
F₁ = P₁ A₁
F₁ = 2.215 10⁷ pi d₁²/4
F₁ = 2.215 10⁷ pi 0.5²/4
F₁ = 4.3 106 N
Answer: 247.67 V
Explanation:
Given
Potential At A ![V_a=382\ V](https://tex.z-dn.net/?f=V_a%3D382%5C%20V)
Potential at ![V_c=785\ V](https://tex.z-dn.net/?f=V_c%3D785%5C%20V)
when particle starts from A it reaches with velocity
at Point while when it starts from C it reaches at point B with velocity ![2v_b](https://tex.z-dn.net/?f=2v_b)
Suppose m is the mass of Particle
Change in Kinetic Energy of particle moving under the Potential From A to B
![q\cdot \left ( V_a-V_b\right )=0.5m\cdot (v_b)^2----1](https://tex.z-dn.net/?f=q%5Ccdot%20%5Cleft%20%28%20V_a-V_b%5Cright%20%29%3D0.5m%5Ccdot%20%28v_b%29%5E2----1)
Change in Kinetic Energy of particle moving under the Potential From C to B
![q\cdot \left ( V_c-V_b\right )=0.5m\cdot (2v_b)^2-----2](https://tex.z-dn.net/?f=q%5Ccdot%20%5Cleft%20%28%20V_c-V_b%5Cright%20%29%3D0.5m%5Ccdot%20%282v_b%29%5E2-----2)
Divide 1 and 2 we get
![\frac{V_a-V_b}{V_c-V_b}=\frac{v_b^2}{4v_b^2}](https://tex.z-dn.net/?f=%5Cfrac%7BV_a-V_b%7D%7BV_c-V_b%7D%3D%5Cfrac%7Bv_b%5E2%7D%7B4v_b%5E2%7D)
on solving we get
![V_b=\frac{4}{3}\cdot V_a-\frac{1}{3}\cdot V_c](https://tex.z-dn.net/?f=V_b%3D%5Cfrac%7B4%7D%7B3%7D%5Ccdot%20V_a-%5Cfrac%7B1%7D%7B3%7D%5Ccdot%20V_c)
![V_b=\frac{743}{3}=247.67\ V](https://tex.z-dn.net/?f=V_b%3D%5Cfrac%7B743%7D%7B3%7D%3D247.67%5C%20V)