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lys-0071 [83]
3 years ago
13

PLEASE HEL WILL GIVE BRAINLIEST TO THE CORRECT ANSWERER

Mathematics
2 answers:
Sav [38]3 years ago
7 0

Answer:

Dilation by 1/2 or 0.5

(x,y)---> (x-2,y-2)

Step-by-step explanation:

Translations needed

     Dilation radius of 2 to radius of 1

     left two  To go left 2 subtract by 2

     Down two   To go down 2 subtract by 2

Pretty straightforward translation, To shrink the radius from 2 to 1: divide by two or multiply by 1/2

When moving up and down: adding to the Y goes up, and subtracting goes down.

When moving left and right adding goes left, and subtracting goes right.

rewona [7]3 years ago
5 0

Answer:

First, Dilation at point A. Then (x, y) → (x -2, y - 2)

Step-by-step explanation:

Dilation will first get the circle to be just as small as Circle C.

After that, (x, y) → (x -2, y - 2) will move the circle 2 to the left and 2 down, right onto Circle C.

The combination of these transformations will carry Circle A onto Circle C.

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9

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Mila Hawkins purchased a bookshelf for $210.00.
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$12.60

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6 0
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Which angles are vertical to DEA? Question is located in the attached file (image)​
ValentinkaMS [17]

Answer:

∠CEB

Step-by-step explanation:

The vertical angle is one that is directly <em>opposite</em> to the original angle. In this image of two intersecting lines, it looks like the angle ∠CEB is directly across from our angle ∠DEA. So, the angle ∠CEB is <em>vertical to</em> ∠DEA.

Hopefully that was helpful! :)

3 0
3 years ago
Given f(x) =
sergejj [24]

Answer:

A

Step-by-step explanation:

We are given the function:

\displaystyle f(x) = \left\{        \begin{array}{ll}            2\cos(\pi x) \text{ for }  x \leq -1 \\ \\          \displaystyle   \frac{2}{\cos(\pi x)}\text{ for } x > -1        \end{array}    \right.

And we want to find:

\displaystyle \lim_{x\to -1}f(x)

So, we need to determine whether or not the limit exists. In other words, we will find the two one-sided limits.

Left-Hand Limit:

\displaystyle \lim_{x\to-1^-}f(x)

Since we are approaching from the left, we will use the first equation:

\displaystyle =\lim_{x\to -1^-}2\cos(\pi x)

By direct substitution:

=2\cos(\pi (-1))=2\cos(-\pi)=2(-1)=-2

Right-Hand Limit:

\displaystyle \lim_{x\to -1^+}f(x)

Since we are approaching from the right, we will use the second equation:

=\displaystyle \lim_{x\to -1^+}\frac{2}{\cos(\pi x)}

Direct substitution:

\displaystyle =\frac{2}{\cos(\pi (-1))}=\frac{2}{\cos(-\pi)}=\frac{2}{(-1)}=-2

So, we can see that:

\displaystyle \displaystyle \lim_{x\to-1^-}f(x)=\displaystyle \lim_{x\to -1^+}f(x) =-2

Since both the left- and right-hand limits exist and equal the same thing, we can conclude that:

\displaystyle \lim_{x \to -1}f(x)=-2

Our answer is A.

8 0
3 years ago
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