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nikdorinn [45]
3 years ago
11

A ____________ are large molecules made up of repeating units, referred to as monomers.

Chemistry
2 answers:
ziro4ka [17]3 years ago
4 0

Answer: polymers

A polymer are large molecules made up of repeating units, referred to as monomers.

Explanation:

Polymers are macromolecule with large size and high molecular mass. They consists of several repeating units of simpler molecules known as monomers.

Examples of polymers found in plants are

- starch composed of several glucose units linked by glycosidic bonds

- cellulose composed of several repeating glucose units linked by glycosidic bonds as well

An example of polymers found in animals is

- glycogen composed of several units of glucose monomers linked by glycosidic bonds

Thepotemich [5.8K]3 years ago
3 0

Answer:

Polymers

Explanation:

Polymers are compounds comprising of Long chain of monomer units produced naturally or artificially .

Polymers are very important in everyday life. Polymers are used in producing automobile parts, healthcare machines, nylons, plastics etc.

Polymers also make up some components of living organisms such as starch , cellulose which are found in plants and are excellent sources of energy.

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Which factor can increase a population rate
Hatshy [7]

Answer:

Factors that cause population growth include increased food production, improved health care services, immigration and high birth rate. These factors have led to overpopulation, which has more negative effects than positive impacts. The world population today is over 7 billion and the number is increasing with each passing year.

Hope this helps!

4 0
3 years ago
What does D represent?
alexandr1967 [171]

Answer:

the lowest point of energy the the graph reaches

3 0
4 years ago
A student dissolves of urea in of a solvent with a density of . The student notices that the volume of the solvent does not chan
Dimas [21]

The question incomplete , the complete question is:

A student dissolves of 18.0 g urea in 200.0 mL of a solvent with a density of 0.95 g/mL . The student notices that the volume of the solvent does not change when the urea dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to significant digits.

Answer:

The molarity and molality of the student's solution is 1.50 Molar and 1.58 molal.

Explanation:

Moles of urea = \frac{18.0 g}{60 g/mol}=0.3 mol

Volume of the solution = 200.0 mL = 0.2 L (1 mL = 0.001 L)

Molarity(M)=\frac{\text{Moles of compound}}{\text{Volume of solution in L}}

Molarity of the urea solution ;

M=\frac{0.3 mol}{0.200 L}=1.50 M

Mass of solvent = m

Volume of solvent = V = 200.0 mL

Density of the urea = d = 0.95 g/mL

m=d\times V=0.95 g/mL\times 200.0 mL=190 g

m = 190 g = 190 \times 0.001 kg = 0.19 kg

(1 g = 0.001 kg)

Molality of the urea solution ;

Molality(m)=\frac{\text{Moles of compound}}{\text{Mass of solvent in kg}}

m=\frac{0.3 mol}{0.19 kg}=1.58 m

The molarity and molality of the student's solution is 1.50 Molar and 1.58 molal.

7 0
3 years ago
100 POINTS!!!!<br><br> Please I need this page done lol
Alenkinab [10]

Answer:

okay.. Questions?????????

5 0
3 years ago
Calculate the change in entropy when 1.00 kg of water at 100 ∘C is vaporized and converted to steam at 100 ∘C. Assume that the h
andrew11 [14]

Answer : The change in entropy is 6.05\times 10^3J/K

Explanation :

Formula used :

\Delta S=\frac{m\times L_v}{T}

where,

\Delta S = change in entropy = ?

m = mass of water = 1.00 kg

L_v = heat of vaporization of water = 2256\times 10^3J/kg

T = temperature = 100^oC=273+100=373K

Now put all the given values in the above formula, we get:

\Delta S=\frac{(1.00kg)\times (2256\times 10^3J/kg)}{373K}

\Delta S=6048.25J/K=6.05\times 10^3J/K

Therefore, the change in entropy is 6.05\times 10^3J/K

5 0
3 years ago
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