CaBr2(s) Ca+2(aq)+2Br-(aq) which means, <span>Solid is turning into free ions so entropy is increasing .</span>
11.0 kg = (11.0 kg)(1000 g/kg) = 11000 g
(11000 g)/(1400 cm3) = 7.857 g/cm3
Simplified = 7.86 g/cm3
Atomic mass W = 183.84 u.m.a
183.84 g ----------- 6.02x10²⁴ atoms
?? g ---------------- 2.1x10²⁴ atoms
2.1x10²⁴ x 183.84 / 6.02x10²⁴ =
3.860x10²⁶ / 6.02x10²⁴ = 641.30 g
hope this helps!
Answer:
CuSO₄(aq) + 2KOH (aq) —> Cu(OH)₂(s) + K₂SO₄(aq)
Explanation:
CuSO₄ + 2KOH —> Cu(OH)₂ + K₂SO₄
To know the state of each compounds, we shall determine the complete ionic equation. This can be obtained as follow:
In solution, CuSO₄ and KOH will dissociate as follow:
CuSO₄(aq) —> Cu²⁺(aq) + SO₄²¯(aq)
KOH (aq) —> K⁺ (aq) + OH¯(aq)
CuSO₄(aq) + KOH (aq) —>
Cu²⁺(aq) + SO₄²¯(aq) + 2K⁺(aq) + 2OH¯(aq) —> Cu(OH)₂(s) + 2K⁺(aq) + SO₄²¯(aq)
Note: Cu(OH)₂ is insoluble in water.
Therefore, the elemental equation is:
CuSO₄(aq) + 2KOH (aq) —> Cu(OH)₂(s) + K₂SO₄(aq)