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aliya0001 [1]
3 years ago
9

What is the period of a wave with a frequancy of 3 Hz and an amplitude off 0.01

Chemistry
1 answer:
lara31 [8.8K]3 years ago
4 0

0.33 seconds is the period of a wave with a frequency of 3 Hz and an amplitude off 0.01 .

<u>Explanation:</u>

We have , period of a wave with a frequency of 3 Hz and an amplitude off 0.01 . We know that period of a wave is amount of time needed to complete one oscillation . In order to calculate period of wave we use frequency and the formula use is period = \frac{1}{frequency} . We are given that frequency = 3 Hz:

period = \frac{1}{frequency}

⇒ period = \frac{1}{frequency}

⇒ period = \frac{1}{3 Hz}

⇒ period = 0.33 seconds

Therefore, 0.33 seconds is the period of a wave with a frequency of 3 Hz and an amplitude off 0.01 .

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(a) 4.12 x 10^15 atoms U
DochEvi [55]

Answer:

1.63ₓ10⁻⁶ g of U

139.03 g of H

0.385 g of O

141.8 g of Pb

Explanation:

In first place, we need to convert the number of atoms to moles, as we know that 1 mol of anything occupies 6.02×10²³ particles

Therefore:

4.12×10¹⁵ atoms of U . 1 mol / 6.02×10²³ atoms = 6.84×10⁻⁹ moles of U

8.37×10²⁵ atoms of H . 1 mol /6.02×10²³ atoms = 139.03 moles of H

1.45×10²² atoms of O . 1 mol /6.02×10²³ atoms = 0.0241 moles of O

4.12×10²³ atoms of Pb . 1 mol /6.02×10²³ atoms = 0.684 moles of Pb

Moles . Molar mass = Mass (g)

6.84×10⁻⁹ moles of U . 238.03 g/mol = 1.63ₓ10⁻⁶ g of U

139.03 moles of H . 1 g/mol = 139.03 g of H

0.0241 moles of O . 16 g/mol = 0.385 g of O

0.684 moles of Pb . 207.2 g/mol = 141.8 g of Pb

8 0
3 years ago
How many dots would the correct Lewis-Dot structure for carbon have? <br> 1 <br> 4 <br> 3 <br> 2
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When creating a Lewis-Dot structure for Carbon, you'll want to put 4 "dots"

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3 years ago
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V125BC [204]
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Dafna11 [192]
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3 years ago
25.2 mL of water are placed in a graduated cylinder. A 22.6 g stone is dropped in, and the water level rises to 32.4 mL. Find th
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<span>Displaced volume :

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