the balanced equation for the acid base reaction is as follows
NaOH + HCl ---> NaCl + H₂O
stoichiometry of NaOH to HCl is 1:1
the number of NaOH moles is - 0.139 mol/L x 0.0154 L = 0.00214 mol
the number of NaOH moles reacted = number of HCl moles reacted
therefore number of HCl moles reacted = 0.00214 mol
volume of HCl containing 0.00214 mol - 25.0 mL
number of HCl moles in 25.0 mL - 0.00214 mol
therefore number of HCl moles in 1000 mL - 0.00214 mol / 25.0 mL x 1000 mL/L
molarity of HCl is 0.0856 mol/L
concentration of HCl is 0.0856 M
The purines in DNA are adenine and guanine, the same as in RNA. The pyrimidines in DNA are cytosine and thymine; in RNA, they are cytosine and uracil. Purines are larger than pyrimidines because they have a two-ring structure while pyrimidines only have a single ring
Temperature is the average amount of energy of motion of each particle of a substance<span>. That is, temperature is a measure of how hot or cold a </span>substance<span> is. In contrast, the total </span>energy of motion<span> in the </span>particles of a substance is called<span> thermal</span>energy<span>.</span>
Ionic bond = chemical bond formed when electrons....
Electrical force = force between two charged ions ....ect
Ionic compound = compounds whose atoms form bonds ......
Crystal = smooth solid formed by repeating patterns.....
Polyatomic ion = ion made of two or more atoms of .....
Answer:
The concentration of COF₂ at equilibrium is 0.296 M.
Explanation:
To solve this equilibrium problem we use an ICE Table. In this table, we recognize 3 stages: Initial(I), Change(C) and Equilibrium(E). In each row we record the <em>concentrations</em> or <em>changes in concentration</em> in that stage. For this reaction:
2 COF₂(g) ⇌ CO₂(g) + CF₄(g)
I 2.00 0 0
C -2x +x +x
E 2.00 - 2x x x
Then, we replace these equilibrium concentrations in the Kc expression, and solve for "x".
![Kc=8.30=\frac{[CO_{2}] \times [CF_{4}] }{[COF_{2}]^{2} } =\frac{x^{2} }{(2.00-2x)^{2} } \\8.30=(\frac{x}{2.00-2x} )^{2} \\\sqrt{8.30} =\frac{x}{2.00-2x}\\5.76-5.76x=x\\x=0.852](https://tex.z-dn.net/?f=Kc%3D8.30%3D%5Cfrac%7B%5BCO_%7B2%7D%5D%20%5Ctimes%20%5BCF_%7B4%7D%5D%20%7D%7B%5BCOF_%7B2%7D%5D%5E%7B2%7D%20%7D%20%3D%5Cfrac%7Bx%5E%7B2%7D%20%7D%7B%282.00-2x%29%5E%7B2%7D%20%7D%20%5C%5C8.30%3D%28%5Cfrac%7Bx%7D%7B2.00-2x%7D%20%29%5E%7B2%7D%20%5C%5C%5Csqrt%7B8.30%7D%20%3D%5Cfrac%7Bx%7D%7B2.00-2x%7D%5C%5C5.76-5.76x%3Dx%5C%5Cx%3D0.852)
The concentration of COF₂ at equilibrium is 2.00 -2x = 2.00 - 2 × 0.852 = 0.296 M
