Answer:
Ahahaha no but thank you. Have a nice day luv! :-))
Answer: 1. A. testable
2.new observations
Explanation:
A scientific theory is the one which explains the cause of a natural phenomena through observatory and experimentation approach. It is valid, accurate and acceptable worldwide.
1. It is testable by implementation of suitable methodology for the purpose of proving the cause of the natural phenomena occurring in nature.
2. A the explanation of the theory can be changes on the basis of the new observations obtained after implementation of new technology and methodology.
Answer:
A catalyst provides an alternative pathway for the reaction, that has a lower activation energy. ... Increasing the temperature will mean there are more particles with high energy, greater than the activation energy, so a higher chance of a successful reaction.
Carbon dioxide, water, energy
Answer:
x = 0.324 M s⁻¹
Explanation:
Equation for the reaction can be represented as:
2 NO(g) + Cl₂ (g) ⇄ 2NOCl (g)
Rate = K [NO]² [Cl₂]
Concentration = 
from the question; their number of moles are constant since the species are quite alike.
As such; if Concentration varies inversely proportional to the volume;
we have: Concentration ∝ 
Concentration = 
Similarly; the Rate can now be expressed as:
Rate = K [NO]² [Cl₂]
Rate =

Rate = 
We were also told that the in the reaction, the gaseous system has an initial volume of 3.00 L and rate of formation of 0.0120 Ms⁻¹
So we can have:
0.0120 = 
0.0120 =
-----Equation (1)
Now; the new rate of formation when the volume of the system decreased to 1.00 L can now be calculated as:
x = 
x = 1 ------- Equation (2)
Dividing equation (2) with equation (1); we have:
= 
= 
x = 0.0120 × 27
x = 0.324 M s⁻¹
∴ the new rate of formation of NOCl = 0.324 M s⁻¹