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3 years ago

12

While a sample of liquid is freezing, its thermal energy

2 answers:

babymother [125]3 years ago

4 0

B. decreases, youre loosing energy

notsponge [240]3 years ago

3 0

Answer:

B

Explanation:

I'm very sure it decreases

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The Environmental Protection Agency (EPA) and the National Highway Traffic Safety Administration (NHTSA) are coordinating standa

Ksivusya [100]

Answer:

Diminish reliance on foreign sources of oil

Explanation:

7 0

3 years ago

Read 2 more answers

A gas is at a pressure of 4.30 atm. what is this pressure in kilopascals? in mm hg?

Monica [59]

Units to measure pressure are as follows
atm - atmospheric pressure units
kPa - kilo Pascals
mm Hg - milimeters Hg
conversion units are;
1 atm = 101 325 Pa
therefore 4.30 atm = 101 325 Pa / atm x 4.30 atm = 435.7 Pa

1 atm = 760.0 mm Hg
4.30 atm = 760.0 mm Hg / atm x 4.30 atm = 3268 mm Hg

answers are 435.7 Pa and 3268 mm Hg

5 0

3 years ago

Read 2 more answers

_NaHCO(s) --> _CO2+_NaCO(s)+_H2O<br><br>balance the equation

elena55 [62]

The balanced equation :

2NaHCO₃⇒CO₂ + Na₂CO₃+H₂O

<h3>Further explanation</h3>

Given

Reaction

NaHCO(s) --> _CO2+_NaCO(s)+_H2O

Required

The balanced equation

Solution

Maybe the equation should be like this :

NaHCO₃⇒CO₂ + Na₂CO₃+H₂O

Give a coefficient

NaHCO₃⇒aCO₂ + bNa₂CO₃+cH₂O

Make an equation

Na, left=1, right=2b⇒2b=1⇒b=1/2

H, left=1, right=2c⇒2c=1⇒c=1/2

C, left=1, right=a+b⇒a+b=1⇒a+1/2=1⇒a=1/2

The equation becomes :

NaHCO₃⇒1/2CO₂ +1/2Na₂CO₃+1/2H₂O x2

2NaHCO₃⇒CO₂ + Na₂CO₃+H₂O

5 0

3 years ago

Which of the following reactions is an example of a single replacement reaction?

chubhunter [2.5K]

The answer is C. Since aluminum reacts with chloride displacing only Copper.

5 0

3 years ago

The constant volume heat capacity of a gas can be measured by observing the decrease in temperature when it expands adiabaticall

miv72 [106K]

Answer:

The value is $C_p = 42. 8 J/K\cdot mol$

Explanation:

From the question we are told that

$\gamma = \frac{C_p }{C_v}$

The initial volume of the fluorocarbon gas is $V_1 = V$

The final volume of the fluorocarbon gas is $V_2 = 2V$

The initial temperature of the fluorocarbon gas is $T_1 = 298.15 K$

The final temperature of the fluorocarbon gas is $T_2 = 248.44 K$

The initial pressure is $P_1 = 202.94\ kPa$

The final pressure is $P_2 = 81.840\ kPa$

Generally the equation for adiabatically reversible expansion is mathematically represented as

$T_2 = T_1 * [ \frac{V_1}{V_2} ]^{\frac{R}{C_v} }$

Here R is the ideal gas constant with the value

$R = 8.314\ J/K \cdot mol$

So

$248.44 = 298.15 * [ \frac{V}{2V} ]^{\frac{8.314}{C_v} }$

=> $C_v = 31.54 J/K\cdot mol$

Generally adiabatic reversible expansion can also be mathematically expressed as

$P_2 V_2^{\gamma} = P_1 V_1^{\gamma}$

=> $[ 81.840 *10^3] [2V]^{\gamma} = [202.94 *10^3] V^{\gamma}$

=> $2^{\gamma} = 2.56$

=> $\gamma = 1.356$

So

$\gamma = \frac{C_p}{C_v} \equiv 1.356 = \frac{C_p}{31.54}$

=> $C_p = 42. 8 J/K\cdot mol$

3 0

3 years ago