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IrinaK [193]
3 years ago
10

SOMEONE HELP NO LINKS PLZ answer Questions 1–6 based on Figure 1.

Chemistry
1 answer:
Bogdan [553]3 years ago
6 0

Answer:

element argon, protons 18 , electrons 18 , outer most energy level 8

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A 20.38 gram sample of cobalt is heated in the presence of excess sulfur. A metal sulfide is formed with a mass of 31.47 g. Dete
Viefleur [7K]

Answer: The empirical formula of the metal sulfide is CoBr_{2}.

Explanation:

Given: Mass of metal = 20.38 g

Mass of metal sulfide = 31.47 g

Moles is the mass of a substance divided by its molar mass.

So, moles of cobalt (molar mass = 59 g/mol) are as follows.

Moles = \frac{mass}{molarmass}\\= \frac{20.38 g}{59 g/mol}\\= 0.345 mol

Moles of bromine (molar mass = 80 g/mol) are as follows.

Moles = \frac{(31.47 - 20.38) g}{80 g/mol}\\= \frac{11.09 g}{80 g/mol}\\= 0.138 mol

Now, the ratio of number of moles of cobalt and number of moles of bromine are as follows.

Moles of Co : Moles of Br = 1 : 2

Hence, the empirical formula is CoBr_{2}.

Thus, we can conclude that the empirical formula of the metal sulfide is CoBr_{2}.

6 0
3 years ago
Unit 3: Energy
Mazyrski [523]

Answer:

What forms of energy does a burning candle give out?

  • The burning candle is converting chemical energy—stored in the hydrocarbon bonds in the wax—into thermal (heat) and radiant (light) energy.

What questions do you have about energy?

  • Can momentum be hidden to human eyes like how kinetic energy can be hidden as heat?
  • Can you go fast enough to get enough mass to become a black hole?
  • How can a material at a certain temperature have all of its molecules at the same energy?
  • How can we travel to the past?

8 0
3 years ago
How did Mendeleev organize the elements in the periodic table?
iren2701 [21]

It is the LAST one in the options.

7 0
4 years ago
Whenever a body is in motion, there is always ____ to oppose the motion.
seropon [69]

Answer:

Force

Explanation:

7 0
3 years ago
Unit: Stoichiometry
Reika [66]

Answer:

1. 2.41 × 1023 formula units

2. 122 L

3. 7.81 L

Explanation:

1. Equation of the reaction: 2 Na(NO3) + Ca(CO3) ---> Na2(CO3) + Ca(NO3)2

Mole ratio of NaNO3 to CaCO3 = 2 : 1

Moles of CaCO3 = mass/molar mass

Mass of CaCO3 = 20 g; molar mass of CaCO3 = 100 g

Moles of CaCO3 = 20 g/100 g/mol = 0.2 moles

Moles of NaNO3 = 2 × 0.2 moles = 0.4 moles

1 Mole of NaNO3 = 6.02 × 10²³ formula units

0.4 moles of NaNO3 = 0.4 × 6.02 × 10²³ = 2.41 × 1023 formula units

2. Equation of reaction : 2 H2O ----> 2 H2 + O2

Mole ratio of oxygen to water = 1 : 2

At STP contains 6.02 × 10²³ molecules = 1 mole of water

6.58 × 10²⁴ molecules = 6.58 × 10²⁴ molecules × 1 mole of water/ 6.02 × 10²³ molecules = 10.93 moles of water

Moles of oxygen gas produced = 10.93÷2 = 5.465 moles of oxygen gas

At STP, 1 mole of oxygen gas = 22.4 L

5.465 moles of oxygen gas = 5.465 moles × 22.4 L/1 mole = 122 L

3.Equation of reaction: 6 K + N2 ----> 2 K3N

Mole ratio of Nitrogen gas and potassium = 6 : 1

Moles potassium = mass/ molar mass

Mass of potassium = 90.0 g, molar mass of potassium = 39.0 g/mol

Moles of potassium = 90.0 g / 39.0 g/mol = 2.3077moles

Moles of Nitrogen gas = 2.3077 moles / 6 = 0.3846 moles

At STP, 1 mole of nitrogen gas = 22.4 L

0.3486 moles of oxygen gas = 0.3486 moles × 22.4 L/1 mole = 7.81 L

7 0
3 years ago
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