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sergey [27]
3 years ago
13

A neutral atom of silicon-30 contains 14 protons. How many electrons does it have?

Chemistry
2 answers:
emmainna [20.7K]3 years ago
3 0
14 as well. A neutral atom has just as many protons in its nucleus and electrons it is electronic shells.
Ostrovityanka [42]3 years ago
3 0
It would also have 14 electrons... -A
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The analysis of 2.12 of a compound gave 0.33 of carbon, 1.82 of the same compound gave 1.53 of sulphur. Calculate the emperical
luda_lava [24]

Answer:

CS₂

Explanation:

To find the empirical formula we need to determine first the percentage of each atom in the molecule. Then, we need to find the moles and, as empirical formula is the simplest whole-number ratio of atoms we can solve the empirical formula:

<em>%C:</em>

0.33gC / 2.12g * 100 = 15.6%

<em>%S:</em>

1.53g S / 1.82g * 100 = 84.1%

In a basis of 100, the moles of each atom are:

<em>C:</em>

15.6g C * (1mol / 12.01g) = 1.30 moles

<em>S:</em>

84.1g S * (1mol / 32.065g) = 2.62 moles

The ratio of Sulphur-Carbon is:

2.62mol / 1.30mol = 2

That means empirical formula is:

<h3>CS₂</h3>
6 0
3 years ago
A 25 g substance has a temperature increase of 17’c when it absorbs 340 J of heat. What is it’s specific heat?
Irina-Kira [14]

Answer:

25 x 17 x 340

Explanation:

5 0
3 years ago
How to find effective nuclear charge
kiruha [24]
The effective nuclear charge is the net positive charge experienced by valence electrons
3 0
3 years ago
1. What is the specific heat (C) of an unknown sample that weighs 5.0 grams, absorbds 250.0j of heat and has a temperature
maks197457 [2]
Note: The question is incomplete. The complete question is given below :
Suppose a substance has a heat of fusion equal to 45 cal/g and a specific heat of 0.75 cal/g°C in the liquid state. If 5.0 kcal of heat are applied to a 50 g sample of the substance at a temperature of 24°C, what will its new temperate be? What state will the sample be in? (melting point of the substance = 27°C; specific heat of the solid =0.48 cal/g°C; boiling point of the substance = 700°C)
Explanation:
1.a) Heat energy required to raise the temperature of the substance to its melting point, H = mcΔT
Mass of solid sample = 50 g; specific heat of solid = 0.75 cal/g; ΔT = 27 - 24 = 3 °C
H = 50 × 0.75 × 3 = 112.5 calories
b) Heat energy required to convert the solid to liquid at its melting point at 27°C, H = m×l, where l = 45 cal/g
H = 50 × 45 = 2250 cal
c) Total energy used so far = 112.5 cal + 2250 cal = 2362.5 calories.
Amount of energy left = 5000 - 2362.5 = 2637.5 cal
The remaining energy is used to heat the liquid
H = mcΔT
Where specific heat of the liquid, c = 0.75 cal/g/°C, H = 2637.5 cal, ΔT = temperature change
2637.5 = 50 × 0.75 x ΔT
ΔT = 2637.5 / ( 50*0.75)
ΔT = 70.3 °C
Final temperature of sample = (70.3 + 27) °C = 97.3 °C
The substance will be in liquid state at a temperature of 97.3 °C

i hope that this eg gonna help u
7 0
2 years ago
If an object is only partially submerged in a fluid, which of the following is true?
Genrish500 [490]
The answer is C. <span>The density of the fluid is greater than the density of the object.</span>
4 0
3 years ago
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