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sergey [27]
3 years ago
13

A neutral atom of silicon-30 contains 14 protons. How many electrons does it have?

Chemistry
2 answers:
emmainna [20.7K]3 years ago
3 0
14 as well. A neutral atom has just as many protons in its nucleus and electrons it is electronic shells.
Ostrovityanka [42]3 years ago
3 0
It would also have 14 electrons... -A
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What other objects are often arranged by their properties
blagie [28]

Answer:

Metaloids and metals.

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3 years ago
A nuclear family consists of
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A biological mother, A biological father and a child
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3 years ago
Problems in Context Which separation method is operating in each of the following procedures? (a) Pouring a mixture of cooked pa
Serga [27]

Answer:

( a ) Filtration

( b ) sugar refining .

Explanation:

( a ) Filtration

By the process of filtration pasta from water can be removed , as pasta is not soluble in water , hence , by filtration , the solid pasta will remain in the filtration funnel , and the water will flow down , thereby , removing pasta from the water .

( b ) sugar refining

The raw sugar can be purified from the process of sugar refining .

7 0
3 years ago
Do parts a, b and c
Leona [35]

Answer:- (a)The pH of the buffer solution is 3.90.

(b) the pH of the solution after addition of HCl would be 3.60.

(c) the pH of the buffer solution after addition of NaOH is 4.32.

Solution:- (a) It is a buffer solution so the pH could easily be calculated using Handerson equation:

pH=Pka+log(\frac{base}{acid})

pKa can be calculated from given Ka value as:

pKa=-logKa

pKa=-log(6.3*10^-^5)

pKa = 4.20

let's plug in the values in the Handerson equation:

pH=4.20+log(\frac{0.025}{0.05})

pH = 4.20 - 0.30

pH = 3.90

The pH of the buffer solution is 3.90.

(b) Let's say the acid is represented by HA and the base is represented by A^- .

Original mili moles of HA from part a = 0.05(100) = 5

original mili moles of A^- from part a = 0.025(100) = 2.5

mili moles of HCl that is H^+ added = 0.100(10.0) = 1

This HCl reacts with the base present in the buffer to make HA as:

A^-+H^+\rightarrow HA

Total mili moles of HA after addition of HCl = 5+1 = 6

mili moles of base after addition of HCl = 2.5-1 = 1.5

Let's plug in the values in the Handerson equation again. Here, we could use the mili moles to calculate the pH. The answer remains same even if we use the concentrations also as the final volume is same both for acid and base.

pH=4.20+log(\frac{1.5}{6})

pH = 4.20 - 0.60

pH = 3.60

So, the pH of the solution after addition of HCl would be 3.60.

(c) mili moles of NaOH or OH^- added to the original buffer = 0.05(15.0) = 0.75

This OH^- reacts with HA to form A^- as:

HA+OH^-\rightarrow H_2O+A^-

mili moles of HA after addition of NaOH = 5-0.75 = 4.25

mili moles of A^- after addition of NaOH = 2.5+0.75 = 3.25

Let's plug in the values again in Handerson equation:

pH=4.20+log(\frac{3.25}{4.25})

pH = 4.20 - 0.12

pH = 4.32

So, the pH of the buffer solution after addition of NaOH is 4.32.

7 0
3 years ago
Which of the statements about peptide bonds are true? The formation of a peptide bond involves a dehydration reaction. A tripept
Mashcka [7]

Answer:

Peptide bonds form from nucleophilic attack by an α‑carboxyl carbon atom on an electron pair of an α‑amino nitrogen atom of another amino acid.

Explanation:

Peptide bond is a form of covalent bond and it is Amide type that is formed between two molecules when carboxyl group react with one molecule of amino group to release molecule of water.The peptide bond are in form pseudo-double bond characteristic; rigid, planar, and stronger than a typical Carboxyl nitrogen single bond.

Peptide bonds form from nucleophilic attack by an α‑carboxyl carbon atom on an electron pair of an α‑amino nitrogen atom of another amino acid.

3 0
3 years ago
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