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PSYCHO15rus [73]
3 years ago
6

In determining the energy of activation, why was it prudent to run the slowest trial done at room temperature in the hot water b

ath and the fastest trial done at room temperature in the cold water bath?
Chemistry
1 answer:
Katen [24]3 years ago
4 0

Answer:In determining the energy of activation, why was it prudent to run the slowest trial done at room temperature in the hot water bath and the fastest trial done at room temperature in the cold water bath?

Explanation:

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Answer:

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Explanation:

Using Hess's law, you can calculate ΔH of any reaction using ΔH°f of products and reactants involed in the reaction.

<em>Hess law: ∑nΔH°f products - ∑nΔH°f reactants = ΔHr</em>

<em>-Where n are moles of reaction-</em>

For the reaction:

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ΔHr = ΔH°f Fe(OH)₃ - ΔH°f Fe³⁺ - 3×ΔH°f OH⁻

Where:

ΔH°f Fe(OH)₃: −824.25 kJ/mol

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Replacing:

ΔHr = −824.25 kJ/mol - (−47.7 kJ/mol) - (3×-229.94 kJ/mol)

<em>ΔHr = -86.73 kJ/mol</em>

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