We know, acceleration = change in velocity / Time
a = 20 - 0 / 3.5
a = 20 / 3.5
a = 5.7 m/s2
In short, Your Answer would be Option B
Hope this helps!
pH is calculated using Handerson- Hasselbalch Equation,
pH = pKa + log [Conjugate Base] / [Acid] --- (1)
Conjugate Base = NaClO
Acid
= HClO
So,
pH = pKa + log [NaClO] / [HClO]
We are having concentration of acid and salt but missing with
pKa,
pKa is calculated as,
pKa = -log Ka
Putting value of Ka,
pKa = -log 2.9 × 10⁻⁸
pKa = 7.53
Now,
Putting all values in eq. 1,
pH = 7.53 + log [0.099] / [0.158]
pH = 7.326
Answer:
1 mole of zinc has 6.023 x 1023 atoms
So, 4.1 moles will have 4.1 x 6.023 x 1023 atoms = 24.694 x 1023 atoms
Explanation:
Answer:
The equation for the precipitation reaction of cobalt (ii) hydroxide is given below:
CoSO₄ (aq) + NaOH (aq) ----> Co(OH)₂ (s) + Na₂SO₄ (aq)
Explanation:
Cobalt (ii) hydroxide is an inorganic compound consisting of cobalt (ii) ions, Co²+ and hydroxide ions, OH-. It is insoluble in water and the pure form known as the beta form is a pink-coloured solid. The impure form which incorporates other anions in its molecular structure is blue in colour and is ustable.
Cobalt (ii) hydroxide is formed as precipitate when an alkaline metallic hydroxide such as sodium hydroxide is mixed with an aqueous cobalt (ii) salt such as cobalt (ii) sulfate. The equation for the precipitation reaction of cobalt (ii) hydroxide is given below:
CoSO₄ (aq) + NaOH (aq) ----> Co(OH)₂ (s) + Na₂SO₄ (aq)
Being a basic hydroxide, cobalt (ii) hydroxide neutralizes acids to form cobalt (ii) salts and water. For example: Co(OH)₂ (s) + H₂SO₄ (aq) ---> CoSO₄ (aq) + H₂O
Thus, cobalt (ii) hydroxide is soluble in acids.
Cobalt(II) hydroxide is used mostly as a drying agent for paints, varnishes, and inks. It is also useful in the preparation of other cobalt compounds.
a) CH2O
each element can be divided by 2
b) BCl3
the molecule is already in it's empirical formula
c) CH4
the molecule is already in it's empirical formula
d)CH2O
each element can be divided by 6