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Rudiy27
4 years ago
7

. A man gave an amount of money to his three sons yao, esi and ampa in the ratio of

Mathematics
1 answer:
arsen [322]4 years ago
6 0

The amount given to them is GHS300.00

Step-by-step explanation:

A man gave an amount of money to his three sons Yao, Esi and Ampa in the ratio of  their years

  • Yao is 15 years
  • Esi is 10 years
  • Ampa 5 years
  • Esi had GHS100.00

We need to find the amount given to them

Let us use the ratio method to solve the problem

∵ Yao is 15 years old

∵ Esi is 10 years old

∵ Ampa is 5 years old

∴ The ratio between them is

→  Yao    :    Esi    :    Ampa

→  15       :    10     :    5

Simplify the terms of the ratio by divide each term by 5

∴ The ratio between their ages in the simplest form is

→  Yao    :    Esi    :    Ampa

→  3         :    2      :    1

∵ Esi had GHS100.00

→  Yao    :    Esi    :    Ampa    :   Total

→  3         :    2      :    1             :   6 ( 3 + 2 + 1 = 6)

→             :  100     :                  :    x

Use the cross multiplication to find x

∵ 2(x) = 100(6)

∴ 2x = 600

- Divide both sides by 2

∴ x = 300

∵ x represents the total money given to them

∴ The amount given to them is GHS300.00

The amount given to them is GHS300.00

Learn more:

You can learn more about the word problems in brainly.com/question/3950386

#LearnwithBrainly

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