Question

A reaction vessel contains 2.50 moles of ci2 and 6.15 moles of f2 how many moles of excess reactant are left

Answer 1

Answer:

2.4moles

Explanation:

Number of moles of Cl₂  = 2.50moles

Number of moles of F₂  = 6.15moles

Unknown:

Moles of excess reactant left = ?

Solution:

The reaction equation:

              Cl₂  +  3F₂   →  2ClF₃

Now, we need to find the excess reactant;

       2 mole of chlorine gas combined with 3 mole of fluorine gas;

      2.5 moles of chlorine gas will combine with $\frac{2.5 x 3}{2}$  = 3.75moles of F₂

The given number of moles of F₂ is 6.15moles

But the reaction needs 3.75 moles

The amount of excess reactant left  = 6.15 - 3.75 = 2.4moles