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Arada [10]
2 years ago
14

2N2 + 3H2 → 2NH3

Chemistry
1 answer:
denis23 [38]2 years ago
3 0

There are two N≡N bonds and three H–H  bonds are in reactants.

Given:

The reaction between nitrogen gas and hydrogen gas.

2N_2+3H_2\rightarrow 2NH_3

To find:

Bonds on the reactant side

Solution:

2N_2+3H_2\rightarrow 2NH_3

Reactants in the reaction = N_2, H_2

The bond between nitrogen atoms in single N_2 molecule  = N≡N (triple bond)

Then in two N_2  molecules = 2 N≡N (triple bonds)

The bond between hydrogen atoms in single H_2 molecule = H-H (single bond)

Then in three H_2  molecules = 3  H-H (single bonds)

Product in the reaction =NH_3

The bonds between nitrogen and hydrogen atoms in single NH_3 molecule = 3 N-H (single bond)

Then in two NH_3  molecules = 6  N-H (single bonds)

So, there are two N≡N bonds and three H–H bonds are in reactants.

Learn more about reactants and products here:

brainly.com/question/21517037?referrer=searchResults

brainly.com/question/20602904?referrer=searchResults

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<h3>Answer:</h3>

3.01 × 10²⁵ molecules H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
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<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
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<h3>Explanation:</h3>

<u>Step 1: Define</u>

50.0 mol H₂O

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />\displaystyle 50.0 \ mol \ H_2O(\frac{6.022 \cdot 10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O} ) = 3.011 × 10²⁵ molecules H₂O

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

3.011 × 10²⁵ molecules H₂O ≈ 3.01 × 10²⁵ molecules H₂O

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