Answer:
The molarity of the acetic acid in this vinegar is 0.853 M
Explanation:
Step 1: Data given
Volume of vinegar sample = 10.00 mL
Concentration of NaOH = 0.5052 M
16.88 mL are required to neutralize the acetic acid
Step 2: The reaction
HC2H3O2(aq) + NaOH(aq) ⇔ NaC2H3O2(aq) + H2O(l)
Step 3: Calculate molarity of cetic acid (HC2H3O2)
C1*V1 = C2*V2
⇒with C1 = the molarity ofHC2H3O2= TO BE DETERMINED
⇒with V1 = the volume of HC2H3O2 = 10.00 mL = 0.01 L
⇒with C2 = the molarity of NaOH = 0.5052 M
⇒with V2 = the volume of NaOH = 16.88 mL = 0.01688L
C1 = (C2*V2)V1
C1 = (0.5052 * 0.01688 ) / 0.01
C1 = 0.853 M
The molarity of the acetic acid in this vinegar is 0.853 M
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Answer:
As electro-negativity decreases from Florine to downwards in the group and only Florine is above Chlorine, so Florine should react with sodium chloride solution to produce chlorine.
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Answer:
- Chlorine
- Bromine
- Iodine
Explanation:
All three of these elements fall in group 7 of the periodic table and are called Halogens. Chlorine is the most reactive of these elements because it comes before the other two in the table then followed by Bromine and then Iodine.
Reactivity decreases in the group 7 elements as one moves to the latter elements due to the increase in shells surrounding the nucleus.
This is because reactivity happens as the protons in the nucleus attract electrons but when more shells are piled on, the strength of this attraction decreases as the distance increases such that they will not be as reactive anymore.
Answer:
If you wash your hands with soap, the soap molecules act as a link between the water you're washing with and the oil on your skin.
Explanation: