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Aliun [14]
4 years ago
11

I NEED HELP PLEASE, THANKS SO MUCH! :)

Chemistry
1 answer:
hjlf4 years ago
5 0

Gases, liquids and solids are all made up of atoms, molecules, and/or ions, but the way the particles inside them differ.

In a gas, the molecules are spread wide apart and moves freely at high speeds

In a liquid, the more closer to each other and will vibrate or slip past each other

In a solid, the molecules are tightly packed, making no room for each other and harder to move. These molecules vibrate and jiggle but, don't move

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Below are shown, for five metals, reduction reactions and standard electrode potential values. which of these metals is the leas
just olya [345]
Above question is incomplete. Complete question is attached below
........................................................................................................................
Solution:
Reduction potential of metal ions are provided below. Higher the value to reduction potential, greater is the tendency of metal to remain in reduced state.

In present case, reduction potential of Au is maximum, hence it is least prone to undergo oxidation. Hence, it is least reactive.

On other hand, reduction potential of Na is minimum, hence it is most prone to undergo oxidation. Hence, it is most reactive. 


7 0
4 years ago
Hi guys,
Nadya [2.5K]

Answer:

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Explanation:

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6 0
3 years ago
Describe the different types of storms.
Genrish500 [490]

Answer:

The different types of storms are hailstorms, ice storms, snowstorms, thunderstorms, wind storms, hurricanes, and tornadoes.

Explanation:

8 0
3 years ago
How many grams of zinc sulfide are used to produce 1.28 grams of zinc oxide?
Lostsunrise [7]

Answer:

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Explanation:

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6 0
3 years ago
In the following reaction, which component acts as an oxidizing agent? 10 I− (aq) + 2 MnO4− (aq) + 16 H+ (aq) → 5 I2 (s) + 2 Mn2
antiseptic1488 [7]

Answer:

The oxidizing agent is the MnO₄⁻

Explanation:

This is the redox reaction:

10 I⁻ (aq) + 2 MnO₄⁻ (aq) + 16 H⁺ (aq) → 5 I₂ (s) + 2 Mn²⁺ (aq) + 8 H2O (l)

Let's determine the oxidation and the reduction.

I⁻ acts with -1 in oxidation state and changes to 0, at I₂.

All elements in ground state has 0 as oxidation state.

As the oxidation state has increased, this is the oxidation, so the iodide is the reducing agent.

In the permanganate (MnO₄⁻), Mn acts with +7 in oxidation state and decreased to Mn²⁺. As the oxidation state is lower, we talk about the reduction. Therefore, the permanganate is the oxidizing agent because it oxidizes iodide to iodine

3 0
3 years ago
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