Answer:
36.9 m/s
Explanation:
From;
v^2 = u^2 + 2as
Where;
v = final velocity =?
a = acceleration = 3.4 m/s^2
u = initial velocity = 0 m/s
s = distance covered = 200 meters
v^2 = 0^2 + 2 * 3.4 * 200
v^2 = 1360
v = √1360
v = 36.9 m/s
Answer:
Explanation:
The figure is not provided and we don't know the force applied to the books.
Therefore, here we are going to assume the force applied is 3 N:
F = 3 N
We can find the acceleration of the stack of books by using Newton's second law of motion, which states that the net force on an object is equal to the product between its mass and its acceleration:
where
F is the force
m is the mass
a is the acceleration
In this problem we have
m = 1.5 kg is the mass of the books
Therefore, the acceleration is:
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