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DerKrebs [107]
3 years ago
10

At 20∘C20 ∘ C, the hole in an aluminum ring is 2.500 cm in diameter. You need to slip this ring over a steel shaft that has a ro

om-temperature diameter of 2.506 cm. To what common temperature should the ring and the shaft be heated so that the ring will just fit onto the shaft?
Physics
1 answer:
Feliz [49]3 years ago
8 0

Answer:

238.75⁰C .

Explanation:

coefficient of linear thermal expansion of aluminum and steel is  23 x 10⁻⁶ K⁻¹ and 12 x 10⁻⁶ K⁻¹ respectively .

Rise in temperature be Δ t .

Formula for linear expansion due to heat is as follows

l = l₀ ( 1 + α x Δt )

l is expanded length , l₀ is initial length , α is coefficient of linear expansion and  Δt is increase in temperature .

For aluminum

l = 2.5 ( 1 +  23 x 10⁻⁶ Δt )

For steel

l = 2.506 ( 1 + 12 x 10⁻⁶ Δt )

Given ,

2.5 ( 1 +  23 x 10⁻⁶ Δt ) = 2.506 ( 1 + 12 x 10⁻⁶ Δt )

1 +  23 x 10⁻⁶ Δt = 1.0024 ( 1 + 12 x 10⁻⁶ Δt )

1 +  23 x 10⁻⁶ Δt = 1.0024   + 12.0288 x 10⁻⁶ Δt

10.9712 x 10⁻⁶ Δt = .0024

Δt = 218.75

Initial temperature = 20⁰C

final temperature = 218.75 + 20 = 238.75⁰C .

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Umnica [9.8K]
<h2>Answer: 10,000 times </h2>

Thomas Alva Edison was a North American scientist and inventor who is credited with the design of the electric bulb and many other patented inventions.

However, the bulb did not come out on the first attempt, and was sometimes questioned by his repeated "failures". But his patience and perseverance paid off, after approximately 10,000 attempts, he managed to obtain an incandescent bulb that would last for a long time.

It should be noted that Edison was once asked if he considered that he had had many failures before making the bulb work, hence his famous phrase:

<h2><em>“I have not failed 10,000 times—I’ve successfully found 10,000 ways that will not work.” </em></h2>

That is why Edison is considered an example of perseverance.

4 0
3 years ago
Problem PageQuestion Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose
Karolina [17]

Answer:

The maximum mass of water that could be produced by the chemical reaction is 10.1 g

Explanation:

The equation of reaction involves the combustion of 2 moles of hexane (C6H14) with 19 moles of oxygen (O2) to produce 12 moles of carbon dioxide (CO2) and 14 moles of water (H2O)

From the equation of reaction above,

2 moles of C6H14 (172 g) produced 14 moles of H2O (252 g)

6.9 g of C6H14 would produce (6.9×252/172) = 10.1 g of water (to 3 significant figures)

Also, from the equation of reaction,

19 moles of O2 (608 g) produced 14 moles of H2O (252 g)

17.3 g of O2 would produce (17.3×252/608) = 7.17 g of water (to 3 significant figures)

Maximum mass of water produced = 10.1 g

3 0
3 years ago
A seesaw has an irregularly distributed mass of 30 kg, a length of 3.0 m, and a fulcrum beneath its midpoint. It is balanced whe
gladu [14]

Answer:

x = 0.9 m

Explanation:

For this exercise we must use the rotational equilibrium relation, we will assume that the counterclockwise rotations are positive

          ∑ τ = 0

          60 1.5 - 78 1.5 + 30 x = 0

where x is measured from the left side of the fulcrum

           90 - 117 + 30 x = 0

           x = 27/30

           x = 0.9 m       

In summary the center of mass is on the side of the lightest weight x = 0.9 m

4 0
4 years ago
What is the origin of cold, wet air masses.
Ber [7]

Answer:

C. over land in polar regions.

7 0
3 years ago
What is the normal force and gravitational force on a 55 kg person standing stationary?
Alex777 [14]

Answer:

539.55 N for both

Explanation:

F=ma

Mass is given at 55kg

And when finding gravitational force gravity's constant is an acceleration of 9.81m/s

F=(55)(9.81)

F= 539.55 N (for both)

Normal force cancels out gravitational force that's why we don't fall throught the floor.

We push down on the floor due to gravitational force but normal force keeps us upright pushing an equal amount back.

4 0
3 years ago
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