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Ludmilka [50]
4 years ago
5

Briefly describe the history of the metric system as it applies to the meter and how the definition of a meter has changed over

time.
Physics
1 answer:
Shalnov [3]4 years ago
8 0

Answer and explanation;

In 1670 Gabriel Mouton, Vicar of St. Paul’s Church and an astronomer proposed the swing  length  of  a  pendulum  with  a  frequency  of  one  beat  per  second  as  the  unit  of length.

In 1791 the Commission of the French Academy of Sciences proposed the name meter to the unit of length. It would equal one tens-millionth of the distance from the North Pole to the equator along the meridian through Paris.It is realistically represented by the distance between two marks on an iron bar kept in Paris.

In 1889 the 1st General Conference on Weights and Measures define the meter as the distance between two lines on a standard bar that made of an alloy of 90%platinum with 10%iridium.

In 1960 the meter was redefined as 1650763.73 wavelengths of orange-red light, in a vacuum, produced by burning the element krypton (Kr-86).

In 1984 the Geneva Conference on Weights and Measures has  defined  the  meter  as  the  distance  light  travels,  in  a  vacuum,  in 1299792458⁄ seconds  with  time  measured  by  a  cesium-133  atomic  clock  which  emits  pulses  of radiation at very rapid, regular intervals.

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If a horse does 4000 J of work over 20 m, how much force does the horse use?
astraxan [27]
In physics, a force is said to do work<span> if, when acting, there is a displacement of the point of application in the direction of the force. It is calculated by the formula W = f x d. Therefore, we calculate the problem above as follows:

W = f x d
4000 = f x 20
f = 200 N <----- FIRST OPTION</span>
5 0
3 years ago
Physics Kinematics question
just olya [345]
An interesting problem, and thanks to the precise heading you put for the question.

We will assume zero air resistance.
We further assume that the angle with vertical is t=53.13 degrees, corresponding to sin(t)=0.8, and therefore cos(t)=0.6.

Given:
angle with vertical, t = 53.13 degrees
sin(t)=0.8; cos(t)=0.6;
air-borne time, T = 20 seconds
initial height, y0 = 800 m

Assume g = -9.81 m/s^2

initial velocity, v m/s (to be determined)

Solution:

(i) Determine initial velocity, v.
initial vertical velocity, vy = vsin(t)=0.8v
Using kinematics equation, 
S(T)=800+(vy)T+(1/2)aT^2 ....(1)  
Where S is height measured from ground.

substitute values in (1):  S(20)=800+(0.8v)T+(-9.81)T^2  =>
v=((1/2)9.81(20^2)-800)/(0.8(20))=72.625 m/s  for T=20 s

(ii) maximum height attained by the bomb
Differentiate (1) with respect to T, and equate to zero to find maximum
dS/dt=(vy)+aT=0 =>
Tmax=-(vy)/a = -0.8*72.625/(-9.81)= 5.9225 s

Maximum height,
Smax
=S(5.9225)
=800+(0.8*122.625)*(5.9225)+(1/2)(-9.81)(5.9225^2)
= 972.0494 m

(iii) Horizontal distance travelled by the bomb while air-borne
Horizontal velocity = vx = vcos(t) = 0.6v = 43.575 m/s
Horizontal distace travelled, Sx = (vx)T = 43.575*20 = 871.5 m

(iv) Velocity of the bomb when it strikes ground
vertical velocity with respect to time
V(T) =vy+aT...................(2)
Substitute values, vy=58.1 m/s, a=-9.81 m/s^2
V(T) = 58.130 + (-9.81)T => 
V(20)=58.130-(9.81)(20) = -138.1 m/s (vertical velocity at strike)

vx = 43.575 m/s (horizontal at strike)
resultant velocity = sqrt(43.575^2+(-138.1)^2) = 144.812 m/s  (magnitude)
in direction theta = atan(43.575,138.1) 
= 17.5 degrees with the vertical, downward and forward. (direction)
4 0
4 years ago
Explain why a scientific theory cannot became a scientific law
Maslowich

A common misconception is that scientific theories are rudimentary ideas that will eventually graduate into scientific laws when enough data and evidence have been accumulated. A theory does not change into a scientific law with the accumulation of new or better evidence.

3 0
3 years ago
1. An electric lamp a marked 240V, 6A. What
Annette [7]

Answer:

The resistance of the lamp is 4Ω.

Explanation:

You have to apply voltage formula :

V = I × R

R = V ÷ I

R = 240 ÷ 60

R = 4 Ω

8 0
3 years ago
An object with a mass of 6.3 kg has a force of 7.1 newtons applied to it.
vlada-n [284]

Answer:

F=ma

7.1=6.3×m

7.1÷6.3=m

m=1.126 kg

6 0
3 years ago
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