Answer:
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Electron’s mass is so small, it can be considered negligible
Answer:
2.28 cm
Explanation:
Radius of the proton if v and B is perpendicular will be,
Now,
mass of proton, .
Radius of the orbit, .
Magnetic field, .
Charge on the proton, .
Now substitute all the variables in r.
.
.
Therefore the radius of the orbit of moving proton is 2.28 cm.
Answer:
1885.2 ohms
Explanation:
Step one:
given data
L=5H
f=60Hz
Required
The inductive reactance of the inductor
Step two:
Applying the expression
XL= 2πfL
substitute
XL=2*3.142*60*5
XL=1885.2 ohms