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Lana71 [14]
2 years ago
11

Three objects of the same mass begin their motion at the same height. One object falls straight down, one slides down a low-fric

tion inclined plane, and one swings in a circular arc on the end of a string. All three objects end at the same height.
In which case does the object have the biggest total work done on it by all forces during its motion?
A. Free Fall
B. Incline
C. String
D. Same
Physics
1 answer:
erik [133]2 years ago
4 0

Answer:

D. Same

Explanation:

Because only gravity is doing the work on the objects, and gravity is constant for all the objects

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A 14.0 gauge copper wire of diameter 1.628 mmcarries a current of 14.0 mA. Part A: What is the potential difference across a 2.1
FrozenT [24]

Answer:

for copper potential difference is 2.4871 × 10^{-4} V

for silver  potential difference is 2.1256 × 10^{-4} V

Explanation:

given data

diameter D = 1.628 mm = 0.001628 m

current = 14.0 mA = 0.0140 A

length L = 2.15 m

to find out

potential difference

solution

we consider here

resistivity of silver =  1.47 × 10^{-8} ohm-m

resistivity of copper = 1.72 × 10^{-8} ohm-m

so we apply here resistance formula that is

Resistance = ρ × L / A     ...............1

so here area A = πr² = π(0.001628 /2)² = 2.0816 ×  10^{-6} m²

for copper Resistance = ρ × L / A

Resistance = 1.72 × 10^{-8}  × 2.15 / 2.0816 ×  10^{-6}

Resistance = 1.7765 × 10^{-2}  ohm

for silver Resistance = ρ × L / A

Resistance = 1.47 × 10^{-8}  × 2.15 / 2.0816 ×  10^{-6}

Resistance = 1.5183 × 10^{-2}  ohm

so

potential difference  is calculated as

for copper potential difference  = current × resistance

potential difference  = 0.0140 ×1.7765 × 10^{-2}

potential difference  = 2.4871 × 10^{-4} V

for silver  potential difference  = current × resistance

potential difference  =  0.0140 × 1.5183 × 10^{-2}

potential difference  =  2.1256 × 10^{-4} V

7 0
2 years ago
Projectile Motion: A hobbyist launches a projectile from ground level on a horizontal plain. It reaches a maximum height of 72.3
marin [14]

Answer:

The angle of launch from the horizontal direction is 20.99° .

Explanation:

Let u and θ be the initial speed and angle of projection from the horizontal axis of the object respectively.

The equations for projectile motion are :

H = ( u² sin²θ)/ 2g      ......(1)

Here H is maximum height of the projectile motion and g is acceleration due to gravity.

R = ( u² sin2θ)/g         .......(2)

Here R is the maximum horizontal displacement of the object.

Rearrange equation (1) in terms of u².

u² = (2gH)/sin²θ

Substitute this equation in equation (2).

R = (2gH sin2θ) / (sin²θ x g)

R = (2H sin2θ)/sin²θ

Using trigonometry property, sin2θ = 2 cosθ sinθ

So, above equation becomes,

R = (2H x 2 cosθ sinθ)/sin²θ

R = (4H cosθ)/sinθ

tanθ = R/4H

θ = tan⁻¹(R/4H)

Substitute 111 m for R and 72.3 m for H in the above equation.

θ = tan⁻¹( 111/ 4 x 72.3 )

θ = tan⁻¹(0.38)

θ = 20.99°

3 0
3 years ago
Electrons are transferred in the formation is blank bonds
densk [106]

Answer:Electrons are transferred in the formation is ionic bonds.

Explanation:Why is because ionic bonds are caused by electrons transferring from one atom to another.

8 0
3 years ago
a proton moves at a speed of 2.0 x 10^7 m/s at right angles to a magnetic field that is directed into the page with a magnitude
nydimaria [60]
The Lorentz force acting on the proton is equal to:
F=qvB \sin \theta
where
q is the proton charge
v is the proton speed
B is the intensity of the magnetic field
\theta is the angle between the direction of v and B

since the proton travels perpendicularly to the magnetic field, in this case \theta=90^{\circ}, so the Lorentz force in this case is simply
F=qvB

The magnetic force provides also the centripetal force that keeps the proton in circular motion:
m \frac{v^2}{r}=qvB
where 
m is the proton mas
r is the radius of the orbit

If we re-arrange this equation and we use the data of the problem, we can find the radius of the orbit:
r= \frac{mv}{qB}= \frac{(1.67 \cdot 10^{-27} kg)(2.0 \cdot 10^7 m/s)}{(1.6 \cdot 10^{-19} C)(0.1 T)} =2.09 m
7 0
3 years ago
Coulomb’s Law relates which of the following?
Verdich [7]
There's nothing on the list you provided that's related to Coulomb's Law.
8 0
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