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Lana71 [14]
3 years ago
11

Three objects of the same mass begin their motion at the same height. One object falls straight down, one slides down a low-fric

tion inclined plane, and one swings in a circular arc on the end of a string. All three objects end at the same height.
In which case does the object have the biggest total work done on it by all forces during its motion?
A. Free Fall
B. Incline
C. String
D. Same
Physics
1 answer:
erik [133]3 years ago
4 0

Answer:

D. Same

Explanation:

Because only gravity is doing the work on the objects, and gravity is constant for all the objects

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Please help <br> Convert the following distance v time graph velocity graph
Reil [10]

Explanation:

for v vs t graph for t=9 to 11,v=15kmph

similarly v2=0,v3=60kmph&v4= -40kmph

5 0
3 years ago
Devise an exponential decay function that fits the given​ data, then answer the accompanying questions. Be sure to identify the
7nadin3 [17]

Answer:

22145.27733 ft

124984.76055 ft

Explanation:

The equation of pressure is

P=P_0e^{-kh}

where,

P_0 =Atmospheric pressure = 800 mbar

k = Constant

h = Altitude = 35000 ft

P=\dfrac{1}{3}P_0

\dfrac{1}{3}P_0=P_0e^{-k35000}\\\Rightarrow \dfrac{1}{3}=e^{-k35000}\\\Rightarrow 3=e^{k35000}\\\Rightarrow ln3=k35000\\\Rightarrow k=\dfrac{ln3}{35000}\\\Rightarrow k=3.13\times 10^{-5}

Now

P=\dfrac{1}{2}P_0

ln2=kh\\\Rightarrow h=\dfrac{ln2}{k}\\\Rightarrow h=\dfrac{ln2}{3.13\times 10^{-5}}\\\Rightarrow h=22145.27733\ ft

The altitude will be 22145.27733 ft

P=0.02P_0

0.02P_0=P_0e^{-kh}\\\Rightarrow 0.02=e^{-3.13\times 10^{-5}h}\\\Rightarrow ln0.02=-3.13\times 10^{-5}h\\\Rightarrow h=\dfrac{ln0.02}{-3.13\times 10^{-5}}\\\Rightarrow h=124984.76055\ ft

The elevation is 124984.76055 ft

6 0
3 years ago
According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of wate
WARRIOR [948]

Answer:

25

Explanation:

Given:

1 can of concentrate requires 3 cans of water

Now,

Total ounces in 200 6-ounce cans = 1200 ounces

also,

for 1 can of concentrate requires 3 cans of water

thus,

for 12 ounces can water can required = 3 × 12 ounces = 36 ounces of cans

Thus,

total ounce of juice per can = 12 + 36 = 48 ounces per can

therefore,

the number of 12-ounce cans required  are = \frac{\textup{Ttoal ounces}}{\textup{Ounces per can}}

or

= \frac{\textup{1200}}{\textup{48}}

or

the number of 12-ounce cans required  are = 25

8 0
3 years ago
A concave lens has a focal length of 20 cm. A real object is 30 cm from the lens. Where is the image? What is the magnification?
Pani-rosa [81]

Answer:

12 cm and 0.4

Explanation:

f = - 20 cm, u = - 30 cm

Let v be the position of image and m be the magnification.

Use lens equation

1 / f = 1 / v - 1 / u

- 1 / 20 = 1 / v + 1 / 30

1 / v = - 5 / 60

v = - 12 cm

m = v / u = - 12 / (-30) = 0.4

6 0
3 years ago
Suppose two wagons, one with twice as much mass as the other, fly apart when a compressed spring that joins them is released. Th
sp2606 [1]

Answer:

The heavier wagon rolls 1/2 as fast as the lighter wagon.

Explanation:

When the compressed spring that joins them is released then the force acts on both wagons will be of equal magnitude but in the opposite direction. However as the mass of one wagon is twice that of other, so the acceleration  will become half of the heavier wagon in comparison with lighter one.

7 0
3 years ago
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