Answer:
to go 20 m/s means that the body travels 20 metres of distance in each second.
Hope it will help :)
Answer:
Explanation:
given,
charge of two spherical drop = 0.1 nC
potential at the surface = 300 V
two drops merge to form a single drop
potential at the surface of new drop = ?
r = 0.003 m
volume = 
= 
= 2.612 × 10⁻⁷ m³
![R =\sqrt[3]{\dfrac{2.612 \times 10^{-7}\times 3}{4\times \pi}}](https://tex.z-dn.net/?f=R%20%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B2.612%20%5Ctimes%2010%5E%7B-7%7D%5Ctimes%203%7D%7B4%5Ctimes%20%5Cpi%7D%7D)
R = 0.00396 m
Answer:
w = 0.173 N
Explanation:
The weigh of any object is computed by multiplying its mass to the acceleration of gravity, so we need to find the gravity on that planet in order to compute the weigh we want.
The ball has a mass of 0.1 kg and its released from a height of 10 m, therefore it is in a free fall motion with gravity acting as a constant acceleration on the body, we can use the equations for free fall movement in order to determine the value for this acceleration:
y(t) = v_0 * t + y_0 - 0.5 * g * t^2
y(t) is the position in the end of the movement, when t = 3.4 s, so y(t) = 0 m.
v_0 is the initial velocity, in this case v_0 = 0 m/s.
y_0 is the initial position of the ball, in this case it is 10 m.
g is the gravity that we want to know.
Applying these values in the equation we have:
0 = 0*(3.4) + 10 - 0.5*g*(3.4)^2
0 = 10 - 0.5*11.56*g
0 = 10 -5.78*g
5.78*g = 10
g = 1.73 m/s^2
Then we can use this value to find out the weigh of the ball in that planet:
w = g*m = 0.1*1.73 = 0.173 N
We know that: 1 L = 100 cL. Or 1 cL = 0.01 L. Then we will make the conversion: 34.9 cL = 34.9 / 100 L = 0.349 L. Also: 1 hL = 100 L. 0.349 L = 0.349 / 100 hL = 0.00349 hL. This can be also written as: 3.49 * 10^(-3) hL ( in the scientific notation ). Answer: 3.49 cL = 0.00349 <span>hL </span>
I searched for you and i think its Velocity. it would be nice if u put the answer choices though
