We know that velocity is equal to the total displacement of an object over time.

Deriving from that equation, we can say that:

Okay, so here it goes:

The bicycle took 25.02 seconds to displace at 58.3 meters.
Answer:
As a mass greater than that of baseball, at the moment of the bowling wave the moment of the baseball ball is also greater
Explanation:
This problem is an application of momentum and momentum. When the astronaut pushed balls, he needed more force to move the ball of greater mass (bowling). The expression for soul is
p = m v
Besibol Blade
p1 = m1 v
Bowling ball
p2 = m2 v
As a mass greater than that of baseball, at the moment of the bowling wave the moment of the baseball ball is also greater
p2 >> p1
Answer:

Explanation:
The horizontal distance covered by the ball in the falling is only determined by its horizontal motion - in fact, it is given by

where
is the horizontal velocity
t is the time of flight
The time of flight, instead, is only determined by the vertical motion of the ball: however, in this problem the vertical velocity is not changed (it is zero in both cases), so the time of flight remains the same.
In the first situation, the horizontal distance covered is

in the second case, the horizontal velocity is increased to

And so the new distance travelled will be

So, the distance increases linearly with the horizontal velocity.
Answer:
Mass of the steel cube = 7800 kg
Volume of the steel = 1.025 cubic centimetre
Explanation:
Given:
The density of the steel = 7.8
Side of the cube = 12 cm
<u>(1)The mass of steel cube :</u>
We know that,

We are given with density and sides of the cube
then volume of the cube
=
= 
= 1000 cubic centimetre
Now


mass = 7800 kg
<u>(2)volume of steel:</u>
Given the mass = 8 kg

Substituting the values


volume = 1.025 cubic centimetre
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