Answer:
1.92 J
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 200 Kg
Spring constant (K) = 10⁶ N/m
Workdone =?
Next, we shall determine the force exerted on the spring. This can be obtained as follow:
Mass (m) = 200 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Force (F) =?
F = m × g
F = 200 × 9.8
F = 1960 N
Next we shall determine the extent to which the spring stretches. This can be obtained as follow:
Spring constant (K) = 10⁶ N/m
Force (F) = 1960 N
Extention (e) =?
F = Ke
1960 = 10⁶ × e
Divide both side by 10⁶
e = 1960 / 10⁶
e = 0.00196 m
Finally, we shall determine energy (Workdone) on the spring as follow:
Spring constant (K) = 10⁶ N/m
Extention (e) = 0.00196 m
Energy (E) =?
E = ½Ke²
E = ½ × 10⁶ × (0.00196)²
E = 1.92 J
Therefore, the Workdone on the spring is 1.92 J
Well, since you only want direction, ignore the numbers. Use the right hand rule.
Current (pointer finger) points west (left).
Magnetic field (middle finger) points south (towards you).
Force (thumb) then points up (away from the earth)
I took the test, A because
(Lo siento si mi español es malo, no es mi primera lengua
)
1. velocidad media = desplazamiento/tiempo
desplazamiento = 0 porque el athelete vuelve al punto inicial en un círculo
velocidad media = desplazamiento/tiempo = 0/10 = 0
2. la distancia entre A y B es 5 cm porque
a^2 + b^2 = c^2 (el teorema de Pitágoras) así:
rapidez media = distancia/tiempo = 5/5 = 1 cm/s o 0.01 m/s
y yo no se cómo hacer 3-5 :( lo siento
3. Creo que es dos triángulo
s AB y CD menos la línea de fondo
5. Creo que es E + F porque B y D b y d cancelarse el uno al otro y C y C tambien pero no lo sé con seguridad.
We can refer that the velocity of a ball for example bounces at a height when throwing the ball toward the floor.
