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Marat540 [252]
3 years ago
13

How are sound waves different from the ripples that spread across water?​

Physics
2 answers:
prisoha [69]3 years ago
6 0

Answer:

.

Explanation:

Sound waves are caused by vibration ripples in water are caused by disturbance in the molecules

Dmitriy789 [7]3 years ago
4 0

Sound waves are longitudinal (the particles move in the same direction as the wave) as opposed to transversal waves (for example, in a sea wave, the water particles move up and down to form the wave). ... Water being incompressible is one of the reasons why sound waves move much faster in water than ripples.

Mark me brainliest please

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The position of an object that is oscillating on a spring is given by the equation x = (17.4 cm) cos[(5.46 s-1)t]. what is the a
bulgar [2K]

The angular frequency of this motion is 5.46 rad/s.

The oscillation of spring is an example of Simple Harmonic Motion(SHM).

The general equation of an SHM is given by the formula.

X = Acos(wt)

Here A is the amplitude

ω is the angular frequency

T is the time

Comparing the above equation with the given condition,

X = 17.4 cm cos(5.46t)

A = 17.4 cm

ω = 5.46 rad/s

T = 1 s

Hence, the angular frequency of this motion is 5.46 rad/s.

To know more about the "general equation of SHM", refer to the link below:

brainly.com/question/14869852?referrer=searchResults

#SPJ4

6 0
2 years ago
1. What is the momentum of a 0.15 kg arrow that is traveling at 120 m/s?
Korvikt [17]

For this case we have that by definition, the momentum equation is given by:

p = m * v

Where:

m: It is the mass

v: It is the velocity

According to the data we have:

m = 0.15 \ kg\\v = 120 \frac {m} {s}

Substituting:

p = 0.15 * 120\\p = 18 \frac {kg * m} {s}

On the other hand, if we clear the variable "mass" we have:

m = \frac {p} {v}

According to the data we have:

p = 250 \frac {kg * m} {s}\\v = 5 \frac {m} {s}\\m = \frac {250} {5}\\m = 50 \ kg

Thus, the mass is 50 \ kg

Answer:

p = 18 \frac {kg * m} {s}\\m = 50 \ kg

3 0
3 years ago
In Case 1, a mass M hangs from a vertical spring having spring constant k and is at rest in its equilibrium position. In Case 2
evablogger [386]

Answer: hello your question is incomplete attached below is the complete question

answer :  1/2 KD^2  ( option A )

Explanation:

P.E ( potential energy ) = mgd

In case 1 P.E = 0   i.e. mgd = 0  

Given that in case 2 the Mass M had moved through the Distance D by the compression of the spring

<u>The potential energy of the M in case 2 </u>

= P.E of M at rest + P.E of the spring

= 0 + 1/2 KD^2

4 0
3 years ago
An elastic band is hung on a hook and a mass is hung on the lower end of the band. When the mass is pulled downward and then rel
pshichka [43]

Answer:

v(t) = s′(t) = −9sin(t)+9cos(t)

a(t) = v′(t) = −9cos(t) −9sin(t)

Explanation:

Given that

s = 9 cos(t) + 9 sin(t), t ≥ 0

Then acceleration and velocity is

v(t) = s′(t) = −9sin(t)+9cos(t)

a(t) = v′(t) = −9cos(t) −9sin(t)

5 0
3 years ago
The first law of thermodynamics invention that spurred its development is
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Energy and matter can neither be created or destroyed.
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3 years ago
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