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Allushta [10]
3 years ago
5

Use a property of exponents to simplify. 3Use as the base.

Mathematics
1 answer:
Mashutka [201]3 years ago
5 0

Answer:

3^4 because when u divide exponents w same base just subtract the exponents

Step-by-step explanation:

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Which statement is true about the end behavior of the graphed function? (ignore my answer)
hoa [83]
The answer is the first choice:

As the x-values go to positive infinity, the functions values go to negative infinity
7 0
3 years ago
A. Complete the chart based on the initial conditions:
Nata [24]

Answer:

a.

Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936

b.

week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g

Step-by-step explanation:

a. From the information provided, we can deduce that the population death's follows a Geometric sequence in the form (a,ar,ar^2,ar^3...) where a-first \ term and r-common \ ratio

#Since the population is reducing, r can is obtained as r=1-r=0.94

#The n^t^h term is obtained using the formula x_n=ar^(^n^-^1^), given a=1200

The number of ants alive after every month (in first 4 months)

Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936

The ant's alive after 4 months is obtained as the value of x_5

x_n=ar^(^n^-^1^)\\1-x_5=1-1200\times 0.94^4=936.89\\\approx 936

Hence, 936 ants are alive after 4 months.

b. As with the above question, the kitten population follows a geometric sequence: (a,ar,ar^2,ar^3...).

#Since it's a growing population , the common ration is the sum of 100% + the growth rate,

r=1.1 and a=80 and x_n=ar^(^n^-^1^)

The population after 4weeks will be:

week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g

8 0
4 years ago
Simplify the radical expression (3 + √6) (3 - √6)
Dmitry_Shevchenko [17]

Answer:

3

Step-by-step explanation:

(3 + √6) (3 - √6) = 9-3√6+3√6-6 = 9-6 = 3

(pls mark brainliest fam)

6 0
3 years ago
Read 2 more answers
Emilie is training for her next track meet. She is running on
Shkiper50 [21]

Answer:

32 laps

Step-by-step explanation:

If each mile is 1600 meters, she will need to run 4 laps per mile. To run 8 miles, multiple the laps for one mile (4) by the total number of miles (8) to get the total laps necessary (32).

Hope this helps!

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3 years ago
Which is the solution to the inequality?<br> 1/4 + x &lt;5/6
Bumek [7]

Answer:

install app photomath ;D

5 0
3 years ago
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