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3 years ago

Use a property of exponents to simplify. 3Use as the base.

Mathematics

1 answer:

Mashutka [201]3 years ago

5 0

Answer:

3^4 because when u divide exponents w same base just subtract the exponents

Step-by-step explanation:

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10(6 + 4 + 5)

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My greatest common factor is 2 and my least common multiple is 12, Whats my number?

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3 years ago

5 of 8

Marina86 [1]

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3 years ago

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What is the equation of the line through (−2, −2) and (4, −5)?

blondinia [14]

Answer:

Step-by-step explanation:

(-5 + 2)/(4 + 2) = -3/6 = -1/2

y + 2 = -1/2(x + 2)

y + 2 = -1/2x - 1

y = -1/2x - 3

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3 years ago

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40 points!!!!!PLEASE HELP!!!!

Alex17521 [72]

Answer: $\frac{\sqrt{26}}{26}$

This is the square root of 26 over 26. The second 26 is not inside the square root. You can type it in as sqrt(26)/26.

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$\theta$ is in Q1 so $\sin(\theta) > 0$

Use the trig identity below and plug in the given value to get...

$\sin\left(\frac{x}{2}\right) = \pm \sqrt{\frac{1-\cos(x)}{2}}\\\\\sin\left(\frac{2\theta}{2}\right) = \pm \sqrt{\frac{1-\cos(2\theta)}{2}}\\\\\sin(\theta) = \sqrt{\frac{1-\cos(2\theta)}{2}} \ \ \text{since } \ \sin(\theta) > 0\\\\\sin(\theta) = \sqrt{\frac{1-\frac{12}{13}}{2}}\\\\$

$\sin(\theta) = \sqrt{\frac{1}{26}}\\\\\sin(\theta) = \frac{\sqrt{1}}{\sqrt{26}}\\\\\sin(\theta) = \frac{1}{\sqrt{26}}\\\\\sin(\theta) = \frac{1*\sqrt{26}}{\sqrt{26}*\sqrt{26}} \ \ \text{ rationalizing denominator}\\\\\sin(\theta) = \frac{\sqrt{26}}{26}\\\\$

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Edit:

To find cos(theta), we use the pythagorean identity below

$\sin^2(\theta) + \cos^2(\theta) = 1\\\\\cos^2(\theta) = 1-\sin^2(\theta)\\\\\cos(\theta) = \sqrt{1-\sin^2(\theta)}\ \ \text{cosine is positive in Q1}\\\\\cos(\theta) = \sqrt{1-\left(\frac{1}{\sqrt{26}}\right)^2}\\\\\cos(\theta) = \sqrt{1-\frac{1}{26}}\\\\\cos(\theta) = \sqrt{\frac{25}{26}}\\\\\cos(\theta) = \frac{\sqrt{25}}{\sqrt{26}}\\\\\cos(\theta) = \frac{5}{\sqrt{26}}\\\\\cos(\theta) = \frac{5\sqrt{26}}{\sqrt{26}*\sqrt{26}}\\\\\cos(\theta) = \frac{5\sqrt{26}}{26}\\\\$

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3 years ago

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