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zhannawk [14.2K]
1 year ago
10

An estimated 40% of all people were born after the year 2000. If two people are selected at random from around the world, what a

re the chances that NEITHER of these people were born after the year 2000?
Mathematics
1 answer:
sukhopar [10]1 year ago
4 0

The chances that NEITHER of these two selected people were born after the year 2000 is 0.36

<h3>How to determine the probability?</h3>

The given parameters are:

Year = 2000

Proportion of people born after 2000, p = 40%

Sample size = 2

The chances that NEITHER of these two selected people were born after the year 2000 is calculated as:

P = (1- p)^2

Substitute the known values in the above equation

P = (1 - 40%)^2

Evaluate the exponent

P = 0.36

Hence, the chances that NEITHER of these two selected people were born after the year 2000 is 0.36

Read more about probability at

brainly.com/question/25870256

#SPJ1

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During a spring clearance sale, Sears advertise 1/4 off the list of Model II microwave ovens and an additional 1/5 off the sale
ozzi

Answer:

$ 75.

Step-by-step explanation:

From the information above,

List price of model II = $240

Sale price of the clearance sale is 1/4 off the list price of Model II microwave oven and additional 1/5 of the sale price for oven that are scratched and dented.

Therefore,

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2 years ago
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Answer:

TRUE

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2x + 0.8/y = z – 4

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3 years ago
Find two positive numbers whose product is 25 and whose sum is a minimum. (if both values are the same number, enter it into bot
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Let xy = 25, x and y > 0.

y = \frac{25}{x}
\text{Denote S as: } x + y
S(x) = x + \frac{25}{x}

\text{Minimum: }S'(x) = 0, S''(x) > 0
S'(x) = 1 - \frac{25}{x^{2}}
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