Your camera determines the focal distance required for your picture to be in focus using the lens equation, , where the focal di
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The value of the variable x = 6 and y = 5. Then the position vector of P will be 6i + 5j.
<h3>What is the equation of a line passing through two points?</h3>The equation of line is given as
y = mx + c
Where m is the slope and c is the y-intercept.
PQRS is a parallelogram. the position vector of Q R and S are 5i +7j, -3i-8j and -4i-6j.
Then the point of Q, R, and S will be (5, 7), (-3, -8), and (-4, -6).
Let the point P be (x, y).
We know that the slope of the line QS and PQ will be same and line is passing through (-3, -8).
y = 1.444x + C
-8 = 1.444 (-3) + C
C = -3.667
Then the equation will be
y = 1.444x – 3.667 …1
The slope of the line PQ and RS will be same and line is passing through (5, 7).
y = -2x + D
7 = -2 (5) + D
D = 17
Then the equation will be
y = -2x + 17 …2
By solving equation 1 and 2, we have
x = 6 and y = 5
Then the position vector of P will be
⇒ 6i + 5j
The graph is given below.
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Answer:
<u>0.765 meters</u> long were the sticks when laid end to end.
Step-by-step explanation:
Given:
Rob laid three sticks end to end. The lengths of the sticks were 45 millimeters, 32 centimeters, and 4 decimeters.
Now, to find the length in meters of the sticks when laid end to end.
The lengths of the sticks are:
1st stick - 45 millimeters.
2nd stick - 32 centimeters.
3rd stick - 4 decimeters.
So, we convert the units of sticks into meters by using conversion factor:
1st stick:
1 millimeter = 0.001 meter.
45 millimeters = 0.001 × 45
45 millimeters = 0.045 meter.
2nd stick:
1 centimeter = 0.01 meter.
32 centimeters = 0.01 × 32
32 centimeters = 0.32 meter.
3rd stick:
1 decimeter = 0.1 meter.
4 decimeters = 0.1 × 4
4 decimeters = 0.4 meter.
Now, adding all the three sticks length to get the the length in meters of the sticks when laid end to end:
Therefore, 0.765 meters long were the sticks when laid end to end.