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rosijanka [135]
3 years ago
8

Find the quotient. Simplify if possible. What is 2/9 divided by (-3/27) ?

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
5 0
\sf \frac{2}{9}:(-\frac{3}{27}^{(3})= \frac{2}{9}* (-9)=\boxed{\sf -2}
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Which is the coefficient in the expression 7x + 14?
guajiro [1.7K]

Answer:

7

Step-by-step explanation:

A coefficient is the number before a variable (x, y, z...etc).

4 0
3 years ago
Perform the indicated opera<br> 6) g(n)= n2 - 1<br> h(n)= 4n+1<br> Find (g. h)n)
DaniilM [7]

(g.h)(n)\,\,is\,\,4n^3+n^2-4n-1\\

Step-by-step explanation:

We are given:

g(n)=n^2-1\\h(n)=4n+1

We need to find (g.h)(n)

Finding (g.h)(n)

(g.h)(n)=g(n).h(n)\\ (g.h)(n)=(n^2-1)(4n+1)\\ (g.h)(n)=n^2(4n+1)-1(4n+1)\\ (g.h)(n)=4n^3+n^2-4n-1\\

So, (g.h)(n)\,\,is\,\,4n^3+n^2-4n-1\\

Keywords: Composite Function

Learn more about Composite Function at:

  • brainly.com/question/10772025
  • brainly.com/question/4939434
  • brainly.com/question/2723982

#learnwithBrainly

6 0
3 years ago
Y'all I need help I'm being timed please
Tpy6a [65]

Answer:

Diana will be able to maek 12

Step-by-step explanation:

8 0
3 years ago
Find the value of b.
Nesterboy [21]

Answer: 230^{\circ

Step-by-step explanation:

For convenience, I labeled some points as shown in the attached picture.

Also, I assume \overline{AB} and \overline{BC} are tangents to the circle.

  1. \overline{BO} \cong \overline{BO} (reflexive property)
  2. \overline{AB} \cong \overline{BC} (tangents drawn from a common external point are congruent)
  3. \angle BAO \cong \angle BCO (right angles are congruent)

Therefore, we know \triangle ABO \cong \triangle CBO by HL.

Thus, by CPCTC,

\angle AOB \cong \angle BOC \implies m\angle BOC=65^{\circ}\\\\\implies m\angle AOC=130^{\circ}

This means the measure of minor arc AC is 130^{\circ}, and thus b=360^{\circ}-130^{\circ}=\boxed{230^{\circ}}

7 0
2 years ago
75 - 3.5y - 4y = 4y + 6 <br> Solve for y please.
Alla [95]

Answer:

6

Step-by-step explanation:

75−3.5y−4y=4y+6

Step 1: Simplify both sides of the equation.

75−3.5y−4y=4y+6

75+−3.5y+−4y=4y+6

(−3.5y+−4y)+(75)=4y+6(Combine Like Terms)

−7.5y+75=4y+6

−7.5y+75=4y+6

Step 2: Subtract 4y from both sides.

−7.5y+75−4y=4y+6−4y

−11.5y+75=6

Step 3: Subtract 75 from both sides.

−11.5y+75−75=6−75

−11.5y=−69

Step 4: Divide both sides by -11.5.

−11.5y

−11.5

=

−69

−11.5

y=6

Hope this helps!

7 0
3 years ago
Read 2 more answers
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