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Mumz [18]
3 years ago
11

If 20 beats are produced within one second, which of the following frequencies could possibly be held by two sound waves traveli

ng through a medium along a common path at the same time?
A. 18 Hz and 26 Hz
B. 47 Hz and 55 Hz
C. 38 Hz and 63 Hz
D. 22 Hz and 42 Hz
Physics
2 answers:
NeTakaya3 years ago
8 0

Answer:

D. 22 Hz and 42 Hz

Explanation:

  • When two waves with different frequency travelling in the same medium meet each other, they produce an interference pattern called beat.
  • <em><u>The frequency of the beat produced is equivalent to </u></em><em><u>the difference between the individual frequencies of the two waves involved.</u></em>
  • <em><u>Therefore; in this case since the frequency of the beat is 20 Hz, that is from 20 beats per second.</u></em>
  • We need to find a pair from the choices whose frequency difference is 20 Hz.
  • This happens to be choice D. 22 Hz and 42 Hz,  that is 42 Hz - 22 Hz = 20 Hz
White raven [17]3 years ago
3 0

Answer:

D. 22 Hz and 42 Hz

Explanation:

bc its pf

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Beats are the difference in (a) Frequency (b) Amplitude (c) Intensity (d) None
sasho [114]

Answer:

Beats are the difference in frequency.

(a) is correct option.

Explanation:

Beat :

Beat is the difference of the frequency of two waves.

The difference in frequency is equal to the number of beat per second.

Amplitude :

Amplitude of the wave is the maximum displacement.

Frequency :

Frequency is the number oscillations of wave in per second.

Intensity :

Intensity is the power per unit area.

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7 0
3 years ago
A planet's moon travels in an approximately circular orbit of radius 7.0 ✕ 10⁷ m with a period of 6 h 38 min. Calculate the mass
natka813 [3]

Answer:

3.56×10²⁶ Kg.

Explanation:

Note: The gravitational force is acting as the centripetal force.

Fg = Fc........................... Equation 1

Where Fg = gravitational Force, Fc = centripetal force.

Recall,

Fg = GMm/r²......................... Equation 2

Fc = mv²/r............................. Equation 3

Where M = mass of the planet, m = mass of the moon, r = radius of the orbit and G = Universal gravitational constant.

Substituting equation 2 and 3 into equation 1

GMm/r² = mv²/r

Simplifying the equation above,

M = v²r/G .............................. Equation 4.

The period of the moon in the orbit

T = 2πr/v

Making v the subject of the equation,

v = 2πr/T............................. Equation 5

where r = 7.0×10⁷ m, T = 6 h 38 min = (6×3600 + 38×60) s = (21600+2280) s

T = 23880 s, π = 3.14

v = (2×3.14×7.0×10⁷ )/23880

v = 18409 m/s

Also Given: G = 6.67×10⁻¹¹ Nm²/kg²

Also substituting into equation 4

M = 18409²×7.0×10⁷ /(6.67×10⁻¹¹)

M = 3.56×10²⁶ Kg.

Thus the mass of the planet =  3.56×10²⁶ Kg.

5 0
3 years ago
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