Question

Before a collision, a 50.0-kg object is moving at +5.0 m/s. Find the impulse that acted on the object if, after the collision, it moves at +17.0 m/s.

Answer 1

Answer:

J=600 kg m/s

Explanation:

Impulse And Momentum

Suppose a particle is moving at a certain speed $v_1$ and changes it to $v_2$. The impulse J is equivalent to the change of linear momentum. The momentum can be computed by

$p=mv$

The initial and final momentums are given, respectively, by:

$p_1=mv_1,\ p_2=mv_2$

Thus, the change of momentum is

$\Delta p=p_2-p_1=m(v_2-v_1)$

It's equal to the Impulse J

$J=\Delta p$

$J=m(v_2-v_1)$

Our data is

$m=50\ kg,\ v_1=5\ m/s,\ v_2=17\ m/s$

$J=50\ (17-5)$

$J=600\ kg\ m/s$