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const2013 [10]
3 years ago
10

Before a collision, a 50.0-kg object is moving at +5.0 m/s. Find the impulse that acted on the object if, after the collision, i

t moves at +17.0 m/s.
Physics
1 answer:
Virty [35]3 years ago
7 0

Answer:

<em>J=600 kg m/s </em>

Explanation:

<u>Impulse And Momentum </u>

Suppose a particle is moving at a certain speed v_1 and changes it to v_2. The impulse J is equivalent to the change of linear momentum. The momentum can be computed by

p=mv

The initial and final momentums are given, respectively, by:

p_1=mv_1,\ p_2=mv_2

Thus, the change of momentum is

\Delta p=p_2-p_1=m(v_2-v_1)

It's equal to the Impulse J

J=\Delta p

J=m(v_2-v_1)

Our data is

m=50\ kg,\ v_1=5\ m/s,\ v_2=17\ m/s

J=50\ (17-5)

J=600\ kg\ m/s

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