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3 years ago

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19. What do the letters CLU stand for in relation to an insurance agent? A. Chartered Life Underwriter B. Chartered Legal Underw

riter C. Certified Legal Underwriter D. Certified Licensed Underwriter

1 answer:

Afina-wow [57]3 years ago

5 0

A. Chartered Life Underwriter B

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Two angles are said to be congruent if:

n200080 [17]

Answer:

C

Step-by-step explanation:

congruent angles have the same angle measure

7 0

3 years ago

Convert 0.656 to a fraction. A. 21⁄32 B. 22⁄30 C. 20⁄33 D. 23⁄12

OlgaM077 [116]

The answer is A. 21/32

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4 years ago

Read 2 more answers

Danielle makes the claim that when the polynomial x^2-3x-10 is divided by x-5, the remainder is 0. Use what you have learned abo

Mumz [18]

Answer:

<h3>Daniel is correct</h3>

Step-by-step explanation:

Given the polynomial P(x) = x^2-3x-10

To check that the remainder is zero if divided by x - 5, we will first have to equate x - 5 to zero and get x;

x - 5 = 0

x = 5

Then find P(5)

P(5) = 5^2 - 3(5) - 10

P(5) = 25 - 15 - 10

P(5) = 25-25

P(5) = 0

<em>This shows that x - 5 is a factor of the polynomial since P(5) gave us zero according to the factor theorem</em>

7 0

3 years ago

How many pairs of whole numbers have a sum of 99?

Dmitry_Shevchenko [17]

There are 50 pairs of whole numbers

5 0

3 years ago

Write an equation that goes through (8,1) and is perpendicular to 2y + 4x =12

Serggg [28]

Answer:

2y -x + 6 = 0

Step-by-step explanation:

Here a equation and a point is given to us and we are interested in finding a equation which is perpendicular to the given equation and passes through the given point .

The given equation is ,

$\sf \longrightarrow 2y + 4x = 12 \\$

$\sf \longrightarrow 4x + 2y = 12$

Firstly convert this into slope intercept form , to find out the slope of the line.

$\sf \longrightarrow 2y = -4x +12\\$

$\sf \longrightarrow y =\dfrac{-4x+12}{2}\\$

$\sf \longrightarrow y =\dfrac{-4x}{2}+\dfrac{12}{2}\\$

$\sf \longrightarrow \red{ y = -2x + 6 }$

Now on comparing it to slope intercept form which is y = mx + c , we have ,

m = -2

And as we know that the product of slopes of two perpendicular lines is -1 . So the slope of the perpendicular line will be negative reciprocal of the slope of the given line. Therefore ,

$\sf \longrightarrow m_{\perp}=\dfrac{-1}{-2}=\red{\dfrac{1}{2}}$

Now we may use the point slope form of the line to find out the equation of the line using the given point . The point slope form is,

$\sf \longrightarrow y - y_1 = m(x - x_1)$

Now on substituting the respective values we have,

$\sf \longrightarrow y - 1 = \dfrac{1}{2}(x-8)\\$

$\sf \longrightarrow 2(y-1 )= x -8 \\$

$\sf \longrightarrow 2y -2=x-8\\$

$\sf \longrightarrow \underline{\boxed{\bf 2y - x + 6=0}}$

5 0

3 years ago