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RideAnS [48]
3 years ago
9

Given f(x) = 2(4 – x)2, what is the value of F(15)? Record your answer and fat in the bubbles on your anser document​

Mathematics
1 answer:
kari74 [83]3 years ago
6 0

Answer:

f(15) = 242

Step-by-step explanation:

Step 1: Define

f(x) = 2(4 - x)²

f(15) = x = 15

Step 2: Substitute and Evaluate

f(15) = 2(4 - 15)²

f(15) = 2(-11)²

f(15) = 2(121)

f(15) = 242

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How many real roots does the function
icang [17]

Answer:

Option C is correct i.e. 2.

Step-by-step explanation:

Given the function is f(x) = x² +8x -2.

We can compare it with general quadratic expression i.e. ax² +bx +c.

Then a = 1, b = 8, c = -2.

We can find the number of real root by finding discriminant of the equation ax² +bx +c =0 as follows:-

D = b² -4ac

D = 8² -4*1*-2

D = 64 +8

D = 72.

When D is a positive value, then we have two real roots of the equation.

Hence, option C is correct i.e. 2.

6 0
3 years ago
Write the number that has 4 thousands,6 humdred thousands,5 ten thousands, 3 tens, and 5 ones
anyanavicka [17]
654,035   654,035     654,035     654,035     654,035     654,035     654,035                          
7 0
3 years ago
The decimal expansion of the number 2 1 / 2​
Molodets [167]

Answer:

{ \tt{ = 2 \frac{1}{2} }} \\  \\   =  \frac{5}{2}  \\  \\ { \tt{ = 2.5}}

4 0
3 years ago
What is the center and radius of -10x = -121 - y2 - x2 -22y
OlgaM077 [116]

We need to find the center and the radius of

-10x\: =\: -121\: -\: y^2\: -\: x^2\: -22y

The general circle equation is the following

(x-h)^2+(y-k)^2=r^2

where

(h,k) is the center and

r is the radius

1. rearrange the equation

(x^2-10x)+(y^2+22y+121)=0

2. Add 25 on both sides

(x^2-10x+25)+(y^2+22y+121)=25

3. Factor

(x-5)^2+(y+11)^2=5^2

Now we have an equation that is very similar to the circle equation, so let's compare them

Center -> (h,k) = (5,-11)

radius -> r = 5

8 0
1 year ago
Rewrite the function by completing the square <br> f(x)=x^2-14x+63
Veseljchak [2.6K]

Answer:

f(x) = (x - 7)² - 14

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Algebra I</u>

  • Standard Form: ax² + bx + c = 0
  • Vertex Form: f(x) = a(bx - c)² + d
  • Completing the Square: (b/2)²

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = x² - 14x + 63

<u>Step 2: Rewrite</u>

  1. Separate:                              f(x) = (x² - 14x) + 63
  2. Complete the Square:         f(x) = (x² - 14x + 49) + 63 - 49
  3. Simplify:                                f(x) = (x - 7)² - 14
8 0
3 years ago
Read 2 more answers
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