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aliya0001 [1]
3 years ago
11

The centripetal force exerted on stunt motorcyclist Biker Bob while riding on the inner vertical surface of a circular track is:

_____
A. Triction
B. His weight
C. The normal force
D. None of the above
Physics
1 answer:
AlladinOne [14]3 years ago
7 0

Answer:

option C

Explanation:

The correct answer is option C.

The normal force is the force exerted by the biker on the inner vertical surface of the circular track.

When the biker move in the circular track centripetal force is acting on the biker which is being balanced by the normal force.

To overcome the gravitation force on the biker the velocity of the biker should be high such that centripetal acceleration of the biker can overcome the gravity force acting on the biker.

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Standing on the roof of a (42.0+A) m tall building, you throw a ball straight up with an initial speed of (14.5+B) m/s. If the b
RSB [31]
First, we must find the vertical distance traveled upwards by the ball due to the throw. For this, we will use the formula:

2as = v² - u²

Because the final velocity v is 0 in such cases

s = -u²/2a; because both u and a are downwards, the negative sign cancels

s = 14.5² / 2*9.81
s = 10.72 meters

Next, to find the time taken to reach the ground, we need the height above the ground. This is:
45 + 10.72 = 55.72 m

We will use the formula 
s = ut + 0.5at²

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55.72 = 0.5 * 9.81 * t²

t = 3.37 seconds
4 0
3 years ago
A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle
MAVERICK [17]

Answer:

t₂ = 3.89 s

Explanation:

given,

speed of car  = 23 m/s

speed of motorcycle = 23 m/s

after time of 4 s distance between them is equal to = 53 m

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time taken to catch up with car = ?

let t₂ be the time in which motorcycle catches car.

distance traveled by car in t₂ s

d = 23 t₂ + 53

distance traveled by motorcycle

using equation of motion

s = ut + \dfrac{1}{2}at^2

s = 23 t_2 + \dfrac{1}{2}\times 7 \times t_2^2

now, equating both the distances

23t_2 + 53= 23 t_2 + \dfrac{1}{2}\times 7 \times t_2^2

t_2^2 = 15.143

    t₂ = 3.89 s

time taken by the motorcycle to catch the car is equal to 3.89 s

4 0
3 years ago
Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The
Greeley [361]

Answer:

I = 215.76 A  

Explanation:

The direction of magnetic field produced by conductor 1 on the location of conductor 2 is towards left. Based on Right Hand Rule -1 and taking figure 21.3 as reference, the direction of force Fm due to magnetic field produced at C_2 is shown above. The force Fm balances the weight of conductor 2.  

Fm = u_o*I^2*L/2*π*d

where I is the current in each rod, d = 0.0082 m is the distance 27rId  

between each, L = 0.85 m is the length of each rod.

Fm = 4π*10^-7*I^2*1.1/2*π*0.0083

The mass of each rod is m = 0.0276 kg  

F_m = mg

4π*10^-7*I^2*1.1/2*π*0.0083=0.0276*9.8

I = 215.76 A  

note:

mathematical calculation maybe wrong or having little bit error but the method is perfectly fine

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3 years ago
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astra-53 [7]

Answer:

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2400*20.5*0.004

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4 0
3 years ago
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