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prisoha [69]
3 years ago
15

During a tennis match, a player serves the ball at a speed s, with the center of the ball leaving the racquet at angle θ below t

he horizontal at a height y0. The net is a distance d away and has a height h. When the ball is directly over the net, what is the distance between them?
Physics
1 answer:
Pachacha [2.7K]3 years ago
5 0

Answer: Maximum distance

= {s²/g} * sine(2*theta)unit

Explanation: This is a projectile motion problem. The horizontal distance between the tennis player and where the tennis reaches over the net is given by the horizontal Range.

Range = {s² * sine2*theta}/g

(s)is the initial speed of projection

Theta is the angle of projection

g is acceleration due to gravity 10m/s².

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Divide (2) by (1)

1m/s =  1/1000 ÷ 1/3600 km/hr

1m/s = 1/1000 × 3600/1  km/hr

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To convert 340m/s to km/hr

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