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Nimfa-mama [501]
2 years ago
15

An object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. The maximum displacement fr

om equilibrium is a and the total mechanical energy of the system is e
Physics
1 answer:
Lady_Fox [76]2 years ago
6 0

An object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. The system's potential energy when kinetic energy of (3/4) E is (1/8) k A².

<h3>What is mechanical energy?</h3>

Mechanical energy is the sum of potential energy and kinetic energy.

Total mechanical energy = P.E max = K.E max

Total mechanical energy = K.E +P.E

Given is the kinetic energy is (3/4)E.

E= (3/4)E + P.E

P.E =  (1/4) E

Maximum potential  energy =E = (1/2) k A²

Here. A is the maximum displacement and k is the spring constant.

The potential energy at kinetic energy of (3/4) E is

P.E = (1/4)E = (1/8) k A²

Therefore, the system's potential energy when kinetic energy of (3/4) E is (1/8) k A².

Learn more about mechanical energy.

brainly.com/question/20904200

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If a object is at rest, does it mean there are no forces acting on it
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If Light is travels from air into pure water with an incident angle of 30°. What is the angle of refraction?
Orlov [11]

Explanation:

For air, n1 = 1.00003; for water, n2 = 1.3330

Given: θ2 = 30 degrees, then

θ1 = arcsin [(n2/n1) sin θ2]

= arcsin [(1.3330/1.0003) sin (40)]

= 58.93 degrees

Note that since, in this example, light is traveling from a medium of higher density (water; n2 = 1.3330) to a medium of lower density (air; n1 = 1.0003), then n2 > n1, and the angle of refraction (θ1) is larger than the angle of incidence (θ2), thus the light bends away from the normal (in this example, the vertical) as it leaves the water and enters the air.

7 0
3 years ago
Find the acceleration that can result from a net force of 20 N exerted on a 2.8-kg
vladimir2022 [97]
Force=mass*acceleration
F=ma

20=2.8a

a=20/2.8

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6 0
3 years ago
Consider an NACA 2412 airfoil with a 2-m chord in an airstream with a velocity of 50 m/s at standard sea level conditions. If th
Akimi4 [234]

Answer:

4°

Explanation:

Given,

chord in the airstream, c = 2 m

speed, v = 50 m/s

lift per unit span = 1353 N/m

density of air, ρ = 1.225 kg/m³

Lift,L = c_L \times \dfrac{1}{2} \rho v^2(c \times s)

\dfrac{L}{s}=c_L \times \dfrac{1}{2} \rho v^2\times c

50=c_L \times 0.5\times 1.225\times 50^2\times 2

c_L = 0.44

From the plot of c_L and angle of attack

Angle of attack is equal to 4°

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