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Nimfa-mama [501]
2 years ago
15

An object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. The maximum displacement fr

om equilibrium is a and the total mechanical energy of the system is e
Physics
1 answer:
Lady_Fox [76]2 years ago
6 0

An object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. The system's potential energy when kinetic energy of (3/4) E is (1/8) k A².

<h3>What is mechanical energy?</h3>

Mechanical energy is the sum of potential energy and kinetic energy.

Total mechanical energy = P.E max = K.E max

Total mechanical energy = K.E +P.E

Given is the kinetic energy is (3/4)E.

E= (3/4)E + P.E

P.E =  (1/4) E

Maximum potential  energy =E = (1/2) k A²

Here. A is the maximum displacement and k is the spring constant.

The potential energy at kinetic energy of (3/4) E is

P.E = (1/4)E = (1/8) k A²

Therefore, the system's potential energy when kinetic energy of (3/4) E is (1/8) k A².

Learn more about mechanical energy.

brainly.com/question/20904200

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Answer:

a) F=2.048\times 10^{-7}\ N

b) a=0.1138\ m.s^{-2}

Explanation:

Given:

  • mass of raindrops, m=1.8\times 10^{-6}\ kg
  • charge on the raindrops, q=+21\times 10^{-12}\ C
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A)

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we have:

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<em>Now force:</em>

F=\frac{1}{4\pi\times 8.854\times 10^{-12}} .\frac{21\times 10^{-12}\times 21\times 10^{-12}}{0.0044^2}

F=2.048\times 10^{-7}\ N

B)

<u>Now the acceleration on the raindrops due to the electrostatic force:</u>

a=\frac{F}{m}

a=\frac{2.048\times 10^{-7}}{1.8\times 10^{-6}}

a=0.1138\ m.s^{-2}

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