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alekssr [168]
3 years ago
7

WILL GIVE BRAINLIEST !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Physics
1 answer:
valina [46]3 years ago
6 0
Gold is a soft metal with a number of properties..It is both malleable and ductille,Also it's a heavy metal ,It is soft,Yellow....etc. Hope that helps
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Block A has a mass of 0.5kg, and block B has a mass of 2kg. Block is is released at a height of 0.75 meters above B. The coeffic
VikaD [51]

Answer:

0.075 m

Explanation:

The picture of the problem is missing: find it in attachment.

At first, block A is released at a distance of

h = 0.75 m

above block B. According to the law of conservation of energy, its initial potential energy is converted into kinetic energy, so we can write:

m_Agh=\frac{1}{2}m_Av_A^2

where

g=9.8 m/s^2 is the acceleration due to gravity

m_A=0.5 kg is the mass of the block

v_A is the speed of the block A just before touching block B

Solving for the speed,

v_A=\sqrt{2gh}=\sqrt{2(9.8)(0.75)}=3.83 m/s

Then, block A collides with block B. The coefficient of restitution in the collision is given by:

e=\frac{v'_B-v'_A}{v_A-v_B}

where:

e = 0.7 is the coefficient of restitution in this case

v_B' is the final velocity of block B

v_A' is the final velocity of block A

v_A=3.83 m/s

v_B=0 is the initial velocity of block B

Solving,

v_B'-v_A'=e(v_A-v_B)=0.7(3.83)=2.68 m/s

Re-arranging it,

v_A'=v_B'-2.68 (1)

Also, the total momentum must be conserved, so we can write:

m_A v_A + m_B v_B = m_A v'_A + m_B v'_B

where

m_B=2 kg

And substituting (1) and all the other values,

m_A v_A = m_A (v_B'-2.68) + m_B v_B'\\v_B' = \frac{m_A v_A +2.68 m_A}{m_A + m_B}=1.30 m/s

This is the velocity of block B after the collision. Then, its kinetic energy is converted into elastic potential energy of the spring when it comes to rest, according to

\frac{1}{2}m_B v_B'^2 = \frac{1}{2}kx^2

where

k = 600 N/m is the spring constant

x is the compression of the spring

And solving for x,

x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(2)(1.30)^2}{600}}=0.075 m

5 0
3 years ago
You and your friends find a rope that hangs down 19m from a high tree branch right at the edge of a river. You find that you can
tangare [24]

Answer:

Explanation:

Given

length of rope L=19\ m

velocity while running v=2\ m/s

when the person jumps off the bank and hang on the rope then we can treat the person as pendulum with Time period T which is given by

T=2\pi \sqrt{\frac{L}{g}}

T=2\pi \sqrt{\frac{19}{9.8}}

T=2\pi \times 1.392

T=8.74\ m/s

Greatest Possible distance will be covered when person reaches the other extreme end  of assumed pendulum (velocity=zero)

therefore he must hang on for 0.5 T time

time=0.5\times 8.74=4.37\ s

5 0
2 years ago
Which of the following correctly describes the hierarchy that exists in the universe? (3 points)
r-ruslan [8.4K]

Answer:

D.

Explanation:

A solar system is a collection of planets, their moons, and other objects in orbit around a central star.

5 0
3 years ago
How many motions variables do each of kinematic equations have
Leni [432]
The answer would be 4, each kinetic equation has 4 variables
3 0
3 years ago
What is the distance to a star whose parallex is 0.1 sec?
Arte-miy333 [17]

Answer:

30.86\times 10^{13} km

Explanation:

Given the parallex of the star is 0.1 sec.

The distance is inversely related with the parallex of the star. Mathematically,

d=\frac{1}{P}

Here, d is the distance to a star which is measured in parsecs, and P is the parallex which is measured in arc seconds.

Now,

d=\frac{1}{0.1}\\d=10 parsec

And also know that,

1 parsec=3.086\times 10^{13} km

Therefore the distance of the star  is 30.86\times 10^{13} km away.

6 0
2 years ago
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