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2 years ago

Can a magnet attract a pure substance?

Physics

1 answer:

Salsk061 [2.6K]2 years ago

3 0

Answer:

Magnets strongly attract materials which already themselves have magnetic domains. They do not significantly attract many metals like gold, aluminum, silver, and even some types of high-chromium stainless-steel, which lack such domains. In fact, pure gold is slightly repelled.

Explanation:

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What is the magnitude of the electric field at the point if the electric potential in the region is given by V 2.00xyz2, where V

Hatshy [7]

Answer:

Electric field at a point ( x , y , z) is $E=-2yz^2-2xz^2-4xyz$ .

Explanation:

Given :

Electric potential in the region is , $V = 2xyz^2\ .$

We need to find the electric field .

We know , electric field , $E=-\dfrac{dV}{dr}$ { Here r is distance }

In coordinate system ,

$E=-\dfrac{dV}{\delta x }-\dfrac{dV}{\delta y }-\dfrac{dV}{\delta z }$ { $\delta$ is partial derivative }

Putting all values we get ,

$E=-\dfrac{2xyz^2}{\delta x }-\dfrac{2xyz^2}{\delta y }-\dfrac{2xyz^2}{\delta z }\\\\E=-2yz^2-2xz^2-4xyz$

Hence , this is the required solution.

3 0

2 years ago

1. Part A

Reika [66]

Answer:

B. 2. A baseball was hit by a bat and now flying through the air.

Explanation: A baseball that is hit by a bat has a larger velocity, due to this the amount of kinetic energy is high.

3 0

2 years ago

if a ball dropped from the top of a building takes 8.2 seconds to hit the ground, how tall is the building?

fgiga [73]

Answer:

This really depends on the size of the ball and if the ball is going straight down or at a diagonal angle

Explanation:

7 0

2 years ago

larisa [96]

Answer:

Aceleración, a = 2 m/s²

Explanation:

Dados los siguientes datos;

Velocidad inicial = 108 km/h

Tiempo = 10 segundos

Velocidad final = 36 km/h

To find the average acceleration;

Conversión:

36 km/h to meters per seconds = 36*1000/3600 = 10 m/s

108 km/h to meters per seconds = 108*1000/3600 = 30 m/s

I. Para encontrar la aceleración, usaríamos la primera ecuación de movimiento;

$V = U + at$

Dónde;

V es la velocidad final.

U es la velocidad inicial.

a es la aceleración.

t es el tiempo medido en segundos.

Sustituyendo en la fórmula, tenemos;

$30 = 10 + a*10$

$30 = 10 + 10a$

$10a = 30 - 10$

$10a = 20$

$Aceleracion = \frac{20}{10}$

Aceleración, a = 2 m/s²

3 0

2 years ago

A spherical capacitor contains a charge of 3.50 nC when connected to a potential difference of 210.0 V. Its plates are separated

Lelu [443]

Incomplete question as we have not told to find what quantity.The complete question is here

A spherical capacitor contains a charge of 3.50 nC when connected to a potential difference of 210.0 V. Its plates are separated by vacuum and the inner radius of the outer shell is 5.00 cm.calculate: (a) the capacitance; (b) the radius of the inner sphere; (c) the electric field just outside the surface of the inner sphere.

Answer:

(a) $C=16.7pF$

(b) $r_{a} =3.749cm$

Explanation:

Given data

$Q=3.50nC\\V=210V\\r_{b}=5.0cm$

For part (a)

The Capacitance given by:

$C=\frac{Q}{V}\\ C=\frac{3.50*10^{-9} C}{210V}\\C=1.6666*10^{-11}F\\or\\C=16.7pF$

For part (b)

The Capacitance of coordinates is given as

$C=\frac{4\pi e}{\frac{1}{r_{a} }-\frac{1}{r_{b} } }\\ So\\{\frac{1}{r_{a} }-\frac{1}{r_{b} } }=\frac{4\pi *8.85*10^{-12} }{1.666*10^{-11}}=6.672m^{-1} \\ \frac{1}{r_{a} }=6.672+(1 /0.05)\\\frac{1}{r_{a} }=26.672\\r_{a} =1/26.672\\r_{a} =0.0375m\\r_{a} =3.749cm$

For part (c)

The electric field according to Gauss Law is given by:

$EA=\frac{Q}{e}\\ E=\frac{Q}{4\pi er_{a}^{2} }=\frac{kQ}{r_{a}^{2}}\\ E=\frac{9*10^{9}*3.50*10^{-9} }{(0.0375m)^{2} }\\ E=2.24*10^{4} N/C$

7 0

3 years ago