All categories

3 years ago

Solve the following system of equations by using either substitution or elimination.

1 answer:

5 0

I believe that the answer to the question provided above are the following;

x = 29.8410

y = 16.6794

z = -1.2642
Hope my answer would be a great help for you. If you have more questions feel free to ask here at Brainly.

You might be interested in

A helicopter carries a 1000-kg-car suspended from a rope below it. The helicopter flies horizontally at a constant speed of 25 m

kolbaska11 [484]

Answer:

(a) Tension, T = 28.653 kN

(b) Wind resistance force, $26.925\ kN$

Solution:

As per the question:

Mass of the car, m = 1000 kg

Speed of the helicopter, v = 25 m/s

Angle made by the rope, $theta = 20^{\circ}$

Now,

(a) To calculate the tension, T in the car:

Tension along the direction of motion, $T_{h} = Tcos20^{\circ}$

Tension along the vertical direction, $T_{v} = Tsin20^{\circ}$

Now, let the force due to the wind directed in the opposite direction of the motion be $F_{W}$ and it balances the horizontal component of the tension, T.

The vertical component is balance by the weight of the car, i.e., mg that acts vertically downwards.

Now,

$T_{v} = mg$

$Tsin20^{\circ} = 1000\times 9.8$

T = 28653 N = 28.653 kN

(b) The force of the wind resistance:

$F_{W} = T_{h}$

$F_{W} = 2cos20^{\circ} = 26925\ N = 26.925\ kN$

If the angle made by the rope with the vertical is $0^{\circ}$ :

$mg = Tsin(90^{\circ} - 0^{\circ})$

$Tsin90^{\circ} = mg = 9800\ N$

The tension in the rope will be equal to the weight the car.

Wind resistance force, $F_{W} = Tcos90^{\circ} = 0\ N$

If the angle made by the rope with the vertical is $90^{\circ}$ :

$mg = Tsin(90^{\circ} - 90^{\circ})$

T = 0 N

Wind resistance force, $F_{W} = Tsin0^{\circ}$

$Tsin0^{\circ} = mg$

$F_{W} = \infty$

There will be no tension in the rope and wind resistance will be infinite.

3 0

3 years ago

A ball on the end of a string is whirled around in a horizontal circle of radius 0.300 m. The plane of the circle is 1.00 m abov

Mamont248 [21]

Answer:

radial acceleration is 41.8 m / s²

Explanation:

The acceleration for circular motion is

a = v² / r

They also give us the X and Y position where the body falls when the rope breaks, let's write the projectile launch equations

x = vox t

y = v₀ₓ t - ½ g t2

Since the circle is horizontally the v₀ₓ is zero (v₀ₓ = 0)

x = v₀ₓ t

t = x / v₀ₓ

y = - ½ g t²

Let's replace and calculate the initial velocity on the X axis

y = - ½ g (x / vox)²

v₀ₓ = √ (g x² / 2 y)

v₀ₓ = √ [- (-9.8) 1.6² / (2 1.00)]

v₀ₓ = 3.54 m / s

This is the horizontal velocity, but since it circle is in horizontal position it is also the velocity of the body at the point of rupture.

Now we can calculate the radial acceleration

a = v² / r

a = 3.54² / 0.300

a = 41.8 m / s²

5 0

3 years ago

which of these best dscribes Earth's mantle? A. most dense layer, consists of the outer and inner parts B. thinnest under the oc

stich3 [128]

C. middle layer, density increases with depth as pressure increases

Explanation:

The mantle is the middle layer of the earth. It's density increases with depth as pressure increases.

Based on the compositional division of the earth, our blue planet is divided into crust, mantle and the core.
The crust is the lightest and the outermost layer of the earth.
The mantle is the middle layer. Its density lies between that of the core and crust.
The mantle is the largest layer and density increases with depth here.
The core is a metallic ball. It is the most dense part of the earth.

Learn more:

Mantle brainly.com/question/10758534

#learnwithBrainly

6 0

3 years ago

Who watching all star draft? Luka better get picked first ong

Whitepunk [10]

Na dame Dolla fo surrrreeeeee

5 0

3 years ago

Read 2 more answers

A 100-m-long wire carrying a current of 4.0 A will be accompanied by a magnetic field of what strength at a distance of 0.050 m