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3 years ago

What is the value of b^2 - 4ac for the following equation? 2x^2 + 3x = -1

Mathematics

1 answer:

Shtirlitz [24]3 years ago

6 0

Hello :
2x²+3x+1=0
a=2 b=3 c=1
b²-4ac = (3)²-4(2)(1) = 1

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X=−12, y=−1/6 The equation is y= . When x=3, y= .

Vera_Pavlovna [14]

Answer:

y=-12,y=-1/6

Step-by-step explanation:

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3 years ago

Is 36, 12, 4, 4/3, 4/9 a geometric sequence?

Mars2501 [29]

Answer:

Step-by-step explanation:

36 : 3 = 12

12 : 3 = 4

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4/3 : 3 = 4/

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3 years ago

5 baseballs to 25 softballs in simplest form

sashaice [31]

Answer:

1/5

Step-by-step explanation:

5 baseballs to 25 softballs

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4 years ago

Read 2 more answers

Match each circular flower bed on the left to its circumference and its area on the right. Some answer options on the right will

marin [14]

Answer:

Bed A --- Third Option

Bed B --- Fifth Option

Step-by-step explanation:

Flower Bed A)

The formula for circumference is:

$C=2\pi r$

The diameter of A is 10 feet. So, its radius is 5 feet.

Substitute 5 for r. So, the circumference of Bed A is:

$C=2\pi (5)=10\pi\text{ feet}$

The formula for the area of a circle is:

$A=\pi r^2$

Substitute 5 for r:

$A=\pi (5)^2$

Square and simplify:

$A=25\pi \text{ square feet}$

So, the circumference of Bed A is 10π feet and its area is 25π square feet.

Therefore, match Bed A to the third option.

Flower Bed B)

The radius of Bed B is 6 feet. Again, we can use the circumference and area formulas. Substitute 6 for r for circumference:

$C=2\pi (6)$

Multiply:

$C=12\pi\text{ feet}$

Substitute 6 for r for the area formula:

$A=\pi(6)^2$

Square and simplify:

$A=36\pi\text{ square feet}$

So, Bed B has a 12π feet circumference and a 36π square feet area.

Therefore, match Bed B to the fifth option.

And we're done!

8 0

3 years ago

A ball was dropped from a height of 60m. Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped. Ho

asambeis [7]

Answer:

The ball traveled 116.25 m when it hit the ground for the fifth term

Step-by-step explanation:

This is a geometric progression exercise and what we are asked to look for is the sum of a GP.

The ball was dropped from a height of 60 m. This means that the initial height of the ball is 60 m.

First value, a = 60

Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped.

This is the common ratio, r = 1/2 = 0.5

The number of terms it hits the ground is the number of terms in the GP.

number of terms, n = 5

The distance traveled by the ball when it hit the ground for the fifth term will be modeled by the equation:

$S_n = \frac{a(1 - r^n) }{1 - r} \\S_5 = \frac{60(1 - 0.5^5) }{1 - 0.5}\\S_5 = \frac{58.125}{0.5} \\S_5 = 116.25 m$

4 0

3 years ago