For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

Where:
m: It's the slope
b: It is the cut-off point with the y axis
On the other hand we have that if two lines are perpendicular, then the product of their slopes is -1. So:

The given line is:

So we have:

We find 

So, a line perpendicular to the one given is of the form:

We substitute the given point to find "b":

Finally we have:

In point-slope form we have:

ANswer:

<span>(a) $7.04
(b) 704/1599
(c) 0.44
(d) 14
(e) $98.56
(a) How much profit does Lucy earn when she sells a necklace?
Since the problem states that her profit is the sale price minus the cost of materials and labor, we have the following equation.
P = $15.99 - $3.38 - $5.57
P = $12.61 - $5.57
P = $7.04
So her profit is $7.04 per necklace.
(b) Write a fraction of the profit per sale price of the necklace. Record your answer as a fraction using whole numbers.
The raw fraction is 7.04/15.99, to get rid of the decimal point, multiply top and bottom by 100, getting 704/1599.
The prime factors of 704 are 2,2,2,2,2,2,11 and the prime factors of 1599 are 3,13,41. Since neither 704, nor 1599 share any common factors, the fraction can't be reduced and the final answer is 704/1599.
(c) What decimal of every dollar of the sale price of the necklace is profit using the fraction from Part (b)?
Pardon the lack of formatting
704/1599 = 0.4403
Rounded to the nearest hundredth gives 0.44
(d) Lucy collected $223.86 selling necklaces at a craft fair. How many necklaces did Lucy sell? Show your work.
This question is asking for total cost. So divide the $223.86 by the sale price of $15.99.
$223.86 / $15.99 = 14
14 necklaces were sold.
(e) How much profit did she earn from the number of necklaces she sold? Show your work.
Since we know from (a) that she has $7.04 profit per necklace, just multiply the amount of profit by the number sold. So
$7.04 * 14 = $98.56</span>
Answer:
I am I supposed to make a number line.
Step-by-step explanation:
Answer:
Graph is attached :)
Step-by-step explanation:
Hope that helps!